Xcode中使用AWS SDK CPP连接S3时MakeShared构造函数报错

在Xcode中尝试用AWS SDK CPP连接并认证S3时，遇到construct_at无匹配函数的错误，AWS官方文档未明确原因。

报错信息 #

/Applications/Xcode.app/Contents/Developer/Platforms/MacOSX.platform/Developer/SDKs/MacOSX13.3.sdk/usr/include/c++/v1/__memory/allocator_traits.h:298:9: No matching function for call to 'construct_at'
/Applications/Xcode.app/Contents/Developer/Platforms/MacOSX.platform/Developer/SDKs/MacOSX13.3.sdk/usr/include/c++/v1/__memory/shared_ptr.h:292:37: In instantiation of function template specialization 'std::allocator_traits<std::allocator<Aws::S3::S3Client>>::construct<Aws::S3::S3Client, std::shared_ptr<SimplifiedAWSCredentialsProvider> &, Aws::Client::ClientConfiguration &, void, void>' requested here

相关代码 #

PTUploader::PTUploader(const std::string& access_key, const std::string& secret_key, const std::string& region)
    : access_key_(access_key),
      secret_key_(secret_key),
      region_(region)
{
    // Initialize the SDK
    options_.loggingOptions.logLevel = Aws::Utils::Logging::LogLevel::Debug;
    Aws::Utils::Logging::InitializeAWSLogging(
        Aws::MakeShared<Aws::Utils::Logging::DefaultLogSystem>(
            "RunUnitTests", Aws::Utils::Logging::LogLevel::Debug, "aws_sdk_"));
    Aws::InitAPI(options_);

    Aws::Client::ClientConfiguration config;
    config.region = region_;

    // Create credentials
    auto credentialsProvider = std::make_shared<SimplifiedAWSCredentialsProvider>(access_key_, secret_key_);

    // Create S3 client with credentials and config
    s3_client_ = std::make_shared<Aws::S3::S3Client>(credentialsProvider, config);
}

这个错误核心是S3Client构造函数参数类型不匹配，具体修复方式如下：

• 确保自定义凭证提供者正确继承父类
  S3Client构造函数要求凭证提供者是std::shared_ptr<Aws::Auth::AWSCredentialsProvider>类型，你的SimplifiedAWSCredentialsProvider必须继承自Aws::Auth::AWSCredentialsProvider，并实现必要的虚函数：

  class SimplifiedAWSCredentialsProvider : public Aws::Auth::AWSCredentialsProvider {
  public:
      Aws::Auth::AWSCredentials GetAWSCredentials() const override {
          return Aws::Auth::AWSCredentials(access_key_, secret_key_);
      }
      // 其他必要实现
  };
  

• 显式转换凭证提供者类型
  若已正确继承仍报错，可显式转换类型以匹配构造函数要求：

  auto credentialsProvider = std::static_pointer_cast<Aws::Auth::AWSCredentialsProvider>(
      std::make_shared<SimplifiedAWSCredentialsProvider>(access_key_, secret_key_)
  );
  s3_client_ = std::make_shared<Aws::S3::S3Client>(credentialsProvider, config);
  

• 改用AWS SDK推荐的Aws::MakeShared
  AWS SDK提供的Aws::MakeShared会处理内部内存分配与类型兼容问题，替换代码中的std::make_shared：

  s3_client_ = Aws::MakeShared<Aws::S3::S3Client>("PTUploader", credentialsProvider, config);
  

• 检查SDK版本与编译配置
  确认使用的AWS SDK CPP版本与代码兼容，同时在Xcode项目设置中，将C++ Language Dialect调整为与SDK编译时一致的标准（如GNU++17或更高）。

内容的提问来源于stack exchange，提问作者Samuel Justice