如何优化根据字符串匹配获取SEWorkflowStates属性值的实现？

相关类与枚举定义如下：

public class SEWorkflow
{
  public SEActions SEAction { get; set; }
  public string nextuser { get; set; }
}

public class SEActions
{
    public SEWorkflowStates OnApprove { get; set; }
    public SEWorkflowStates OnReject { get; set; }
    public SEWorkflowStates OnSubmit { get; set; }
}
public enum SEWorkflowStates
{
    Nothing,
    DonotDisturb,
}

我持有SEWorkflow实例，还有值为OnApprove/OnReject/OnSubmit的字符串变量action，目前通过if分支实现根据action匹配SEActions中对应属性、获取SEWorkflowStates值：

public SEWorkflowStates mapper(SEWorkflow workflow, string action)
{
  // action = OnApprove or OnReject or OnSubmit 
  if(action == "OnApprove")
  {
    return workflow.SEActions.OnApprove;
  }
  if(action == "OnReject")
  {
    return workflow.SEActions.OnReject;
  }
  if(action == "OnSubmit")
  {
    return workflow.SEActions.OnSubmit;
  }
  return SEWorkflowStates.Nothing;
}

但这种if写法较为繁琐，请问是否有更优的实现方式？

1. 字典映射（推荐：性能稳定、易维护） #

提前创建静态字典，将字符串action映射到属性获取委托，后续新增属性仅需更新字典：

// 作为类的静态成员，避免重复创建
private static readonly Dictionary<string, Func<SEActions, SEWorkflowStates>> _actionMappings = new()
{
    ["OnApprove"] = actions => actions.OnApprove,
    ["OnReject"] = actions => actions.OnReject,
    ["OnSubmit"] = actions => actions.OnSubmit
};

public SEWorkflowStates mapper(SEWorkflow workflow, string action)
{
    if (_actionMappings.TryGetValue(action, out var getter))
    {
        return getter(workflow.SEActions);
    }
    // 处理无效action的默认逻辑
    return SEWorkflowStates.Nothing;
}

2. 反射+缓存（适合属性较多场景） #

通过反射根据属性名直接取值，搭配缓存避免重复反射开销：

private static readonly Dictionary<string, PropertyInfo> _propertyCache = new();

public SEWorkflowStates mapper(SEWorkflow workflow, string action)
{
    if (!_propertyCache.TryGetValue(action, out var property))
    {
        property = typeof(SEActions).GetProperty(action);
        if (property == null || property.PropertyType != typeof(SEWorkflowStates))
        {
            return SEWorkflowStates.Nothing;
        }
        _propertyCache[action] = property;
    }
    return (SEWorkflowStates)property.GetValue(workflow.SEActions);
}

3. 枚举替代字符串（从根源优化） #

若可修改方法参数类型，定义对应操作的枚举，用C#模式匹配简化逻辑，还能避免字符串拼写错误：

public enum WorkflowAction
{
    OnApprove,
    OnReject,
    OnSubmit
}

public SEWorkflowStates mapper(SEWorkflow workflow, WorkflowAction action)
{
    return action switch
    {
        WorkflowAction.OnApprove => workflow.SEActions.OnApprove,
        WorkflowAction.OnReject => workflow.SEActions.OnReject,
        WorkflowAction.OnSubmit => workflow.SEActions.OnSubmit,
        _ => SEWorkflowStates.Nothing
    };
}

内容的提问来源于stack exchange，提问作者Venkat