如何用python-docx获取段落对齐值？解决部分段落对齐值无法获取问题

我正尝试使用python-docx自动化处理docx文件格式，需要获取段落的对齐值。现有代码对大部分段落有效，但测试文档中索引为11、文本为“O Congresso Nacional decreta:”的段落，视觉上为两端对齐（justify），但通过以下代码获取的a1、a2、a3均为None：

for paragraph in doc.paragraphs:
    a1 = paragraph.alignment
    a2 = paragraph.style.paragraph_format.alignment
    a3 = paragraph.style.base_style.paragraph_format.alignment

请问对齐信息还可能存储在什么位置？

对齐值可能存储在样式的多层继承链中，仅检查一层父样式是不够的，需要循环遍历整个继承链直到base_style为None。可能的存储位置包括：

paragraph.alignment
paragraph.style.paragraph_format.alignment
paragraph.style.base_style.paragraph_format.alignment
paragraph.style.base_style.base_style.paragraph_format.alignment
paragraph.style.base_style.base_style.base_style.paragraph_format.alignment

更高效的实现方式是通过循环自动遍历所有父样式，直到找到非None的对齐值或遍历结束：

def get_paragraph_alignment(paragraph):
    # 优先检查段落自身的对齐设置
    alignment = paragraph.alignment
    if alignment is not None:
        return alignment
    # 遍历样式继承链
    current_style = paragraph.style
    while current_style is not None:
        alignment = current_style.paragraph_format.alignment
        if alignment is not None:
            return alignment
        current_style = current_style.base_style
    # 若未找到，返回None或默认对齐方式
    return None

内容的提问来源于stack exchange，提问作者pedmacedo