添加输入语句后出现TypeError: 'str' object is not callable错误的原因？

错误原因 #

你将Python内置的input()函数名用作了自定义变量名。执行input = input("What would you like to do?\n")后，原本的input函数被覆盖成了用户输入的字符串对象。后续再调用input(...)时，实际是尝试调用一个字符串，而字符串不可被调用，因此抛出TypeError: 'str' object is not callable错误。

解决办法 #

将自定义变量名改为与内置函数不冲突的名称，比如action、user_choice等，避免覆盖内置函数。

修改后的代码示例 #

import random
password = 0

print("Password Generator")

# 替换变量名为action，避免覆盖内置input函数
action = input("What would you like to do?\n")
app = str(input("For what application would you like to generate a password\n"))
n = int(input("How many characters would you like in your password?\n"))

chars = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z','A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z','0','1','2','3','4','5','6','7','8','9','!','@','#','$']

password = random.choice(chars)
i = 0

for i in range(n-1):
    password = password + random.choice(chars)

print(f"Your password is: {password}")

with open('passwordlist.txt', 'a') as f:
    f.write(f"{app} : {password}\n")

内容的提问来源于stack exchange，提问作者ShrekLover