Python入门问题：如何打印星期名称而非关联的工时整数值？

我是Python初学者，完成作业时需要获取用户输入的工作日工时（整数），生成汇总信息并根据工时判断打印某天工时过多或不足的提示。但当前代码里，把星期作为变量名存储工时数值，打印提示时只输出工时数字而非星期名称（比如输出“Too many hours worked on 9”而非“Too many hours worked on Monday”）。

我的代码如下：

week = input("Enter Current Working Week: ")
id = input("Enter Employee ID: ")
name = input("Enter Employee Name: ")
monday = int(input("Enter hours worked for Monday: "))
tuesday = int(input("Enter hours worked for Tuesday: "))
wednesday = int(input("Enter hours worked for Wednesday: "))
thursday = int(input("Enter hours worked for Thursday: "))
friday = int(input("Enter hours worked for Friday: "))

print("Summary for Employee", id,)
for i in monday, tuesday, wednesday, thursday, friday:
    if i > 8:
        print("Too many hours worked on", monday, tuesday, wednesday, thursday, friday)
    elif i < 4:
     print("Insufficient hours worked on", monday, tuesday, wednesday, thursday, friday)) 

请问如何改进代码以输出包含星期名称的正确提示？

核心问题是单独存储星期工时的方式，无法把工时数值和对应的星期名称关联起来。解决思路是将星期名称与对应工时配对存储，比如用列表嵌套元组的方式，遍历的时候就能同时拿到星期名和工时。

改进后的代码如下：

week = input("Enter Current Working Week: ")
emp_id = input("Enter Employee ID: ")  # 避免用id做变量名，它是Python内置函数
name = input("Enter Employee Name: ")

# 用列表存储星期名称和对应工时的配对
work_hours = []
days = ["Monday", "Tuesday", "Wednesday", "Thursday", "Friday"]
for day in days:
    hours = int(input(f"Enter hours worked for {day}: "))
    work_hours.append( (day, hours) )

print(f"Summary for Employee {emp_id}")
total_hours = 0
for day, hours in work_hours:
    total_hours += hours
    if hours > 8:
        print(f"Too many hours worked on {day}")
    elif hours < 4:
        print(f"Insufficient hours worked on {day}")

# 补充总工时汇总，完善输出内容
print(f"Total hours worked this week: {total_hours}")

关键改进说明： #

• 用days列表统一存储星期名称，通过循环收集输入，避免重复编写input语句，代码更简洁
• 用元组(day, hours)绑定星期名和工时，遍历过程中可同时获取两者，解决名称与数值对应问题
• 将变量名id改为emp_id，避免覆盖Python内置的id()函数
• 使用f-string格式化输出，提升代码可读性
• 修复原代码中循环print会输出所有工时、末尾多余右括号的语法错误
• 新增总工时计算，让汇总信息更完整

内容的提问来源于stack exchange，提问作者Sharon9091