如何在PHPUnit中断言关联数组数组中特定键值条件是否满足？

问题背景 #

给定以下PHP数组：

$result = [
   [
      "lable" => "first", ["type" => "customer", "balance" => 1000],
   ],
   [
      "lable" => "another", ["type" => "retailer", "balance" => 1500],
   ],
];

需要编写PHPUnit测试，完成两个断言：

• 断言数组中存在balance大于1200的项
• 断言数组中存在type为customer的项

测试实现方案 #

方法一：提取字段结合PHPUnit内置断言 #

通过array_map提取目标字段，再用assertContains和assertThat完成断言：

public function testResultArrayAssertions()
{
    $result = [
        [
            "lable" => "first", ["type" => "customer", "balance" => 1000],
        ],
        [
            "lable" => "another", ["type" => "retailer", "balance" => 1500],
        ],
    ];

    // 断言存在balance大于1200的项
    $balances = array_map(fn($item) => $item[1]['balance'], $result);
    $this->assertThat(
        $balances,
        $this->logicalOr(...array_map(fn($b) => $this->greaterThan(1200), $balances))
    );

    // 断言存在type为customer的项
    $types = array_map(fn($item) => $item[1]['type'], $result);
    $this->assertContains('customer', $types);
}

方法二：遍历数组直接判断 #

通过遍历数组检查条件，再用assertTrue断言结果：

public function testResultArrayAssertions()
{
    $result = [
        [
            "lable" => "first", ["type" => "customer", "balance" => 1000],
        ],
        [
            "lable" => "another", ["type" => "retailer", "balance" => 1500],
        ],
    ];

    $hasHighBalance = false;
    $hasCustomerType = false;

    foreach ($result as $item) {
        if ($item[1]['balance'] > 1200) {
            $hasHighBalance = true;
        }
        if ($item[1]['type'] === 'customer') {
            $hasCustomerType = true;
        }
    }

    $this->assertTrue($hasHighBalance, '数组中不存在balance大于1200的项');
    $this->assertTrue($hasCustomerType, '数组中不存在type为customer的项');
}

注意事项 #

原数组的结构需要特别注意：每个子数组的第二个元素是嵌套的关联数组，因此提取字段时必须使用$item[1]['balance']和$item[1]['type']的语法。

内容的提问来源于stack exchange，提问作者Navid_pdp11