Python石头剪刀布游戏异常：玩家1始终获胜的修复咨询

问题描述 #

我用Python写了一款石头剪刀布游戏，原本想根据玩家选择判定胜负，但实际运行时总是显示玩家1获胜。请问怎么让游戏按规则在玩家2该赢的时候判定胜利？

原代码：

print("Welcome to Rock, Paper, Scissors!")
print("Use R for Rock , P for Paper and S for Scissors")
print()
n = input("Do you want name? (Y/N) :")
if n == "yes" or n == "Yes" or n == "Y" or n == "y":
  p1n = input("Name for player 1? :")
  p2n = input("Name for player 2? :")
  name = True
else:
  name = False
from getpass import getpass as input
p1=input("What do you choose?(R,P or S)(p1): ")
p2=input("What do you choose?(R,P or S)(p2): ")
if p1 == "paper" or p1 == "Paper" or p1 == "p" or p1 == "P" and p2 == "rock" or p2 == "Rock" or p2 == "r" or p2 == "R":
  print("Player 1 has won! GG!😈")
  if name == True:
    print(p1n,"has won! GG!😈")
elif p1 == "rock" or p1 == "Rock" or p1 == "r" or p1 == "R" and p2 == "scissors" or p2 == "Scissors" or p2 == "s" or p2 == "S":
  print("Player 1 has won! GG!😈")
  if name == True:
    print(p1n,"has won! GG!😈")
elif p1 == "scissors" or p1 == "Scissors" or p1 == "s" or p1 == "S" and p2 == "paper" or p2 == "Paper" or p2 == "p" or p2 == "P":
  print("Player 1 has won! GG!😈")
  if name == True:
    print(p1n,"has won! GG!😈")
elif p1 == "rock" or p1 == "Rock" or p1 == "r" or p1 == "R" and p2 == "rock" or p2 == "Rock" or p2 == "r" or p2 == "R":
  print("Its a tie! LOL 💀🤣!")
elif p1 == "paper" or p1 == "Paper" or p1 == "p" or p1 == "P" and p2 == "paper" or p2 == "Paper" or p2 == "p" or p2 == "P":
  print("Its a tie! LOL 💀🤣!")
elif p1 == "scissors" or p1 == "Scissors" or p1 == "s" or p1 == "S" and p2 == "scissors" or p2 == "Scissors" or p2 == "s" or p2 == "S":
  print("Its a tie! LOL 💀🤣!")
elif p2 == "rock" or p2 == "Rock" or p2 == "r" or p2 == "R" and p1 == "scissors" or p1 == "Scissors" or p1 == "s" or p1 == "S":
  print("Player 2 has won! Well Played!😎")
  if name == True:
    print(p2n,"has won! Well Played!😎")
elif p2 == "paper" or p2 == "Paper" or p2 == "p" or p2 == "P" and p1 == "rock" or p1 == "Rock" or p1 == "r" or p1 == "R":
  print("Player 2 has won! Well Played!😎")
  if name == True:
    print(p2n,"has won! Well Played!😎")
elif p2 == "scissors" or p2 == "Scissors" or p2 == "s" or p2 == "S" and p1 == "paper" or p1 == "Paper" or p1 == "p" or p1 == "P":
  print("Player 2 has won! Well Played!😎")
  if name == True:
    print(p2n,"has won! Well Played!😎")
else:
  print("Don't trick me dumbo!(And if u put scissor intead of scissors then its not my fault!)")

问题根源 #

核心问题是逻辑运算符优先级错误：Python中and的优先级高于or，导致你的条件判断完全不符合预期。比如第一个if语句：

if p1 == "paper" or p1 == "Paper" or p1 == "p" or p1 == "P" and p2 == "rock" ...

实际执行逻辑是：只要p1是"paper"/"Paper"/"p"/"P"，不管p2是什么，条件都会成立，直接判定玩家1获胜。因为p1 == "P" and p2 == "rock"是一个整体，但前面的or只要有一个为真，整个条件就为真。

修复方案 #

1. 给条件分组加括号 #

把每个玩家的选择条件用括号括起来，确保逻辑正确。比如：

if (p1 == "paper" or p1 == "Paper" or p1 == "p" or p1 == "P") and (p2 == "rock" or p2 == "Rock" or p2 == "r" or p2 == "R"):

这样只有当p1是纸且p2是石头时，才触发玩家1获胜的条件。

2. 优化输入处理（可选但推荐） #

把输入统一转成小写（或大写），减少重复的判断语句，让代码更简洁。比如：

p1 = input("What do you choose?(R,P or S)(p1): ").lower()
p2 = input("What do you choose?(R,P or S)(p2): ").lower()

之后只需要判断p1 == 'p'或者p1 == 'paper'即可，不用再区分大小写。

修改后的完整代码 #

print("Welcome to Rock, Paper, Scissors!")
print("Use R for Rock , P for Paper and S for Scissors")
print()
n = input("Do you want name? (Y/N) :").lower()
name = False
p1n = p2n = ""
if n in ["yes", "y"]:
    p1n = input("Name for player 1? :")
    p2n = input("Name for player 2? :")
    name = True

from getpass import getpass as input
# 统一转小写，简化判断
p1 = input("What do you choose?(R,P or S)(p1): ").lower()
p2 = input("What do you choose?(R,P or S)(p2): ").lower()

# 玩家1获胜的条件，分组加括号
if (p1 == "paper" or p1 == "p") and (p2 == "rock" or p2 == "r"):
    print("Player 1 has won! GG!😈")
    if name:
        print(f"{p1n} has won! GG!😈")
elif (p1 == "rock" or p1 == "r") and (p2 == "scissors" or p2 == "s"):
    print("Player 1 has won! GG!😈")
    if name:
        print(f"{p1n} has won! GG!😈")
elif (p1 == "scissors" or p1 == "s") and (p2 == "paper" or p2 == "p"):
    print("Player 1 has won! GG!😈")
    if name:
        print(f"{p1n} has won! GG!😈")
# 平局条件
elif p1 == p2 or (p1 in ["rock", "r"] and p2 in ["rock", "r"]) or (p1 in ["paper", "p"] and p2 in ["paper", "p"]) or (p1 in ["scissors", "s"] and p2 in ["scissors", "s"]):
    print("Its a tie! LOL 💀🤣!")
# 玩家2获胜的条件
elif (p2 == "paper" or p2 == "p") and (p1 == "rock" or p1 == "r"):
    print("Player 2 has won! Well Played!😎")
    if name:
        print(f"{p2n} has won! Well Played!😎")
elif (p2 == "rock" or p2 == "r") and (p1 == "scissors" or p1 == "s"):
    print("Player 2 has won! Well Played!😎")
    if name:
        print(f"{p2n} has won! Well Played!😎")
elif (p2 == "scissors" or p2 == "s") and (p1 == "paper" or p1 == "p"):
    print("Player 2 has won! Well Played!😎")
    if name:
        print(f"{p2n} has won! Well Played!😎")
else:
    print("Don't trick me dumbo!(And if u put scissor instead of scissors then its not my fault!)")

关键说明 #

• 所有玩家选择的判断都用括号明确分组，确保and和or的逻辑顺序正确。
• 输入转小写后，只需要判断小写的字符和单词，减少冗余代码。
• 平局条件简化为直接判断p1和p2是否匹配，或者对应选项是否一致，更简洁。

内容的提问来源于stack exchange，提问作者ToxicGamer329