如何在discord.py 2.0.0中获取Bot对象的User_ID？

我正在使用discord.py 2.0.0开发Discord机器人，想要实现一个斜杠命令来返回Bot对象的用户ID，以下是我的简化代码：

import discord
from discord.ext.commands import Bot
intents = discord.Intents.all()
client = Bot(command_prefix='?', intents=intents)
tree = client.tree
@tree.command(name="help", description="Help command")
async def help(interaction: discord.Interaction):
    await interaction.response.send_message(f"Hello, I am {str(client.id)}")

token = "My Token"
client.run(token)

我尝试通过Bot.id属性获取机器人的用户ID，但出现了属性不存在的错误，报错信息如下：

Traceback (most recent call last):
  File "C:\Users\trnt\AppData\Local\Programs\Python\Python310\lib\site-packages\discord\app_commands\commands.py", line 851, in _do_call
    return await self._callback(interaction, **params)  # type: ignore
  File "C:\discordbot\bot.py", line 8, in help
    await interaction.response.send_message(f"Hello, I am {str(client.id)}")
AttributeError: 'Bot' object has no attribute 'id'

The above exception was the direct cause of the following exception:

Traceback (most recent call last):
  File "C:\Users\trnt\AppData\Local\Programs\Python\Python310\lib\site-packages\discord\app_commands\tree.py", line 1240, in _call
    await command._invoke_with_namespace(interaction, namespace)
  File "C:\Users\trnt\AppData\Local\Programs\Python\Python310\lib\site-packages\discord\app_commands\commands.py", line 876, in _invoke_with_namespace
    return await self._do_call(interaction, transformed_values)
  File "C:\Users\trnt\AppData\Local\Programs\Python\Python310\lib\site-packages\discord\app_commands\commands.py", line 869, in _do_call
    raise CommandInvokeError(self, e) from e
discord.app_commands.errors.CommandInvokeError: Command 'help' raised an exception: AttributeError: 'Bot' object has no attribute 'id'

Bot对象本身没有id属性，要获取机器人的用户ID，需通过client.user.id来实现。Bot类继承自Client类，Client的user属性对应机器人的User对象，该对象包含id属性。

修正后的代码如下：

import discord
from discord.ext.commands import Bot
intents = discord.Intents.all()
client = Bot(command_prefix='?', intents=intents)
tree = client.tree

@client.event
async def on_ready():
    await tree.sync()  # 同步斜杠命令到服务器
    print(f"已登录为 {client.user} (ID: {client.user.id})")

@tree.command(name="help", description="Help command")
async def help(interaction: discord.Interaction):
    # 确保机器人已完成登录初始化
    if client.user is None:
        await interaction.response.send_message("机器人尚未就绪！")
        return
    await interaction.response.send_message(f"你好，我是 {client.user} (ID: {client.user.id})")

token = "My Token"
client.run(token)

补充说明 #

• 机器人完成登录后，client.user才会被初始化，建议在on_ready事件触发后再执行相关操作，或在命令中加入判断避免报错。
• 斜杠命令必须调用tree.sync()同步到Discord服务器，否则用户无法触发命令。

内容的提问来源于stack exchange，提问作者turrnut