Flutter中RawKeyboardListener长按中心按钮重复触发问题求助

在使用RawKeyboardListener实现电视遥控器按键控制时，长按中心按钮（keyCode 23）会重复执行对应功能，我们可以通过维护按键的按下状态来实现仅响应单次按压的需求。

修改方案 #

核心思路是记录当前处于按下状态的按键，仅在首次按下时触发功能，按键松开后清除记录，以此避免长按重复触发。由于需要维护状态，需将原StatelessWidget改为StatefulWidget：

import 'package:flutter/material.dart';
import 'package:flutter/services.dart';

class RawKeyboardListenerWidget extends StatefulWidget {
  final Widget child;
  final FocusNode focusNode;
  final void Function(int) remoteControlKeys;

  const RawKeyboardListenerWidget({
    Key? key,
    required this.child,
    required this.focusNode,
    required this.remoteControlKeys,
  }) : super(key: key);

  @override
  State<RawKeyboardListenerWidget> createState() => _RawKeyboardListenerWidgetState();
}

class _RawKeyboardListenerWidgetState extends State<RawKeyboardListenerWidget> {
  // 存储当前处于按下状态的按键code
  final Set<int> _activePressedKeys = {};

  @override
  Widget build(BuildContext context) {
    return RawKeyboardListener(
      focusNode: widget.focusNode,
      onKey: (RawKeyEvent event) {
        if (event.data is RawKeyEventDataAndroid) {
          final keyData = event.data as RawKeyEventDataAndroid;
          final keyCode = keyData.keyCode;

          if (event is RawKeyDownEvent) {
            // 仅当按键未被标记为按下时，才执行逻辑
            if (!_activePressedKeys.contains(keyCode)) {
              _activePressedKeys.add(keyCode);
              widget.remoteControlKeys(keyCode);

              if (keyCode == 23) {
                //_handleCenterOrEnterKeyPress();
              } else if (keyCode == 20) {
                //_handleDownKeyPress();
              } else if (keyCode == 19) {
                //_handleUpKeyPress();
              } else if (keyCode == 22) {
                //_handleRightKeyPress();
              } else if (keyCode == 21) {
                //_handleLeftKeyPress();
              }
            }
          } else if (event is RawKeyUpEvent) {
            // 按键松开时，移除标记
            _activePressedKeys.remove(keyCode);
          }
        }
      },
      child: widget.child,
    );
  }
}

关键逻辑说明 #

• 使用_activePressedKeys集合跟踪当前按下的按键，确保每个按键仅在首次按下时触发一次功能
• 当收到RawKeyDownEvent时，先检查按键是否已在集合中：不在则执行逻辑并加入集合，已存在则跳过（对应长按重复触发的情况）
• 收到RawKeyUpEvent时，将按键从集合中移除，保证下次按压能正常响应

内容的提问来源于stack exchange，提问作者Mohammed Helewa