Discord Python Bot无法响应命令，报错'TextChannel' object is not callable

参照YouTube视频开发Discord Python Bot，程序编译通过且Bot已上线，但无法响应命令。控制台输出如下：

rug#5048 is now running!
rugmaster76 said: "hello" (general)
'TextChannel' object is not callable

发送"hello"时，Bot应回复"Hey there!"，相关代码如下：

bot.py #

import discord
import responses


async def send_message(message, user_message, is_private):
    try:
        response = responses.get_response(user_message)
        await message.author.send(response) if is_private else await message.channel(response)

    except Exception as e:
        print(e)


def run_discord_bot():
    TOKEN = 'MTEyODExMDc4NDA4MjM1NDIxNg.GLoasi.NN3Yy2kbyDJ4yBGhPloDE3onIEhQU5OpzumtM4'
    intents = discord.Intents.default()
    intents.message_content = True
    client = discord.Client(intents=intents)

    @client.event
    async def on_ready():
        print(f'{client.user} is now running!')

    @client.event
    async def on_message(message):
        if message.author == client.user:
            return

        username = str(message.author)
        user_message = str(message.content)
        channel = str(message.channel)

        print(f'{username} said: "{user_message}" ({channel})')

        if user_message[0] == '?':
            user_message = user_message[1:]
            await send_message(message, user_message, is_private=True)
        else:
            await send_message(message, user_message, is_private=False)


    client.run(TOKEN)

responses.py #

import random


def get_response(message: str) -> str:
    p_message = message.lower()

    if p_message == 'hello':
        return 'Hey there!'

    if message == 'roll':
        return str(random.randint(1, 6))

    if p_message == '!help':
        return'`this is a help message that u can modify`'

    return 'i didnt understand what u wrote, try typing "!help."'

main.py #

import bot

if __name__ == '__main__':
    bot.run_discord_bot()

核心错误修复 #

控制台报错'TextChannel' object is not callable，原因是message.channel是频道对象，不能直接调用，需要使用send()方法发送消息。修改bot.py中的send_message函数：

async def send_message(message, user_message, is_private):
    try:
        response = responses.get_response(user_message)
        # 将 message.channel(response) 改为 message.channel.send(response)
        await message.author.send(response) if is_private else await message.channel.send(response)
    except Exception as e:
        print(e)

潜在问题优化 #

1. 命令大小写兼容：responses.py中roll命令未转小写，用户输入大写或混合大小写时无法触发，修改为：

# 原代码：if message == 'roll':
if p_message == 'roll':
    return str(random.randint(1, 6))

2. 空输入防护：当用户只输入?时，user_message[0] == '?'会触发索引错误，在bot.py的on_message函数中添加长度判断：

# 原代码：if user_message[0] == '?':
if len(user_message) > 0 and user_message[0] == '?':
    user_message = user_message[1:]
    await send_message(message, user_message, is_private=True)

修改后Bot即可正常响应"hello"等命令。

内容的提问来源于stack exchange，提问作者Rug Master