Titanium iOS应用运行时Swift编译标志报错求助

我开发了一款基于Titanium的iOS应用，此前运行正常，但突然出现以下错误：

[ERROR] warning: conditional compilation flags do not have values in Swift; they are either present or absent (rather than 'DEPLOYTYPE=development')
[ERROR] warning: conditional compilation flags do not have values in Swift; they are either present or absent (rather than '__LOG__ID__=e06779ed-4e79-4f3a-84d0-ab3d79067099')
[ERROR] warning: conditional compilation flags do not have values in Swift; they are either present or absent (rather than 'DEBUG=1')
[ERROR] warning: conditional compilation flags do not have values in Swift; they are either present or absent (rather than 'DISABLE_TI_LOG_SERVER=1')
[ERROR] warning: conditional compilation flags do not have values in Swift; they are either present or absent (rather than 'TI_VERSION=12.1.2')
[ERROR] ** BUILD FAILED **
[ERROR] The following build commands failed:
[ERROR]         Ld /Users/myuser/Documents/Appcelerator_Studio_Workspace/myProject/build/iphone/build/Products/Debug-iphonesimulator/myProject.app/myProject normal (in target 'myProject' from project 'myProject')
[ERROR] (1 failure)
Process exited with 1

我已在项目build文件夹的.xcodeproj文件中找到这些标志，尝试修改后，每次运行项目该文件都会重新编译，标志也会恢复原状。请问该如何解决此问题？

解决方案 #

• 禁止直接修改build目录下的Xcode项目文件：该目录由Titanium构建流程自动生成，每次构建都会覆盖手动修改内容，修改操作无效。
• 升级Titanium SDK版本：当前使用的12.1.2版本可能存在Swift条件编译标志的兼容性问题，建议升级至最新稳定版，新版本通常会修复这类编译冲突。
• 调整tiapp.xml中的构建配置：
  • 移除所有带=xxx格式的条件编译配置项，Swift仅支持“存在/不存在”的标志逻辑，比如将DEPLOYTYPE=development改为仅保留DEPLOYTYPE。
  • 系统默认的标志（如DEBUG）无需手动赋值，Titanium会根据构建模式自动处理。
• 清理构建缓存：
  • 删除项目根目录下的build文件夹，重新执行构建命令。
  • 清理Xcode衍生数据：打开Xcode，进入Xcode > Preferences > Locations，点击Derived Data旁的箭头打开文件夹，删除对应项目的缓存文件。
• 排查第三方模块：部分第三方Titanium模块可能会注入带值的编译标志导致冲突，可暂时禁用模块逐个排查，定位问题来源。

内容的提问来源于stack exchange，提问作者Manuel_Rodrigues