Quasar中如何移除对象内指定键对应的条目？

你在Quasar中拥有如下结构的对象：

{
  1: {id: 1, title: 'Supreme Court dubs Manipur', news: 'PTI, New Delhi, JUL 20 2023, 11:23 ISTUPDATED: JUL…isturbing-asks-centre-to-take-action-1238849.html', created_by: 10000001, updated_by: null},
  2: {id: 2, title: 'test for reverse', news: 'reverse test In the above program, the user is pro…d to enter a string. That string is passed to the', created_by: 10000001, updated_by: 10000001},
  12: {id: 12, title: 'cc', news: 'cc', created_by: 10000001, updated_by: null},
  13: {id: 13, title: 'aa', news: 'aa', created_by: 10000001, updated_by: null},
  14: {id: 14, title: 'jj', news: 'jj', created_by: 10000001, updated_by: null},
  15: {id: 15, title: 'mm', news: 'h', created_by: 10000001, updated_by: null}
}

你尝试用以下代码移除键为12的条目：

let id = 12
master.news.splice(id, 1)

但触发报错：Uncaught TypeError: master.news.splice is not a function

问题原因 #

splice是数组的专属方法，而master.news是键值对格式的对象，数据类型不匹配，因此无法调用该方法。

解决方案 #

删除对象的指定键值对，可使用以下两种方法：

1. 直接修改原对象（操作简单）
   用JavaScript原生delete操作符直接移除目标键：

let id = 12
delete master.news[id]

2. 生成新对象保留原数据
   若需保留原对象，可通过解构赋值创建排除目标键的新对象：

let id = 12
const { [id]: _, ...newNews } = master.news
master.news = newNews

内容的提问来源于stack exchange，提问作者Sona Rijesh