Swift中如何让SearchBar实现首字符匹配而非全字符搜索?
实现Swift搜索栏仅匹配开头字符的解决方案
当前代码的问题在于使用range(of:options:)时未指定锚定规则,导致只要字符串包含搜索内容就会被匹配(比如输入“Co”会同时命中Conejo和Sacoja)。要实现仅匹配开头字符的需求,可通过以下两种方式修改:
方式一:修改range(of:)的匹配选项
给range(of:)的options参数添加.anchored选项,强制匹配仅从字符串起始位置开始,同时修正代码中$0.text的笔误(数组元素本身是String类型,无需.text属性):
listEmployed = ["Conejo","Tetera","Aviteon","Sacoja"] func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) { isSearching = true arrayFilterEmployed = listEmployed if !searchText.isEmpty { let lowercasedSearchText = searchText.lowercased() arrayFilterEmployed = listEmployed.filter { $0.lowercased().range(of: lowercasedSearchText, options: [.caseInsensitive, .anchored]) != nil } } if arrayFilterEmployed?.count == 0 { searchBar.showsCancelButton = false fountLabel?.isHidden = false } else { categoryTableView?.reloadData() fountLabel?.isHidden = true } categoryTableView?.reloadData() }
方式二:使用hasPrefix方法(更简洁直观)
直接调用String的hasPrefix方法,结合大小写转换实现不区分大小写的前缀匹配:
listEmployed = ["Conejo","Tetera","Aviteon","Sacoja"] func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) { isSearching = true arrayFilterEmployed = listEmployed if !searchText.isEmpty { let lowercasedSearchText = searchText.lowercased() arrayFilterEmployed = listEmployed.filter { $0.lowercased().hasPrefix(lowercasedSearchText) } } if arrayFilterEmployed?.count == 0 { searchBar.showsCancelButton = false fountLabel?.isHidden = false } else { categoryTableView?.reloadData() fountLabel?.isHidden = true } categoryTableView?.reloadData() }
两种方式都能实现输入“Co”时仅返回Conejo的需求。
内容的提问来源于stack exchange,提问作者Mauriho Enrique Escurra Colqui
相关产品推荐
相关产品推荐

