Python中使用函数实现分数筛选与对应姓名输出的问题求解

Hey there! Let's sort out your code and get the result you're looking for. First, let's break down where your current implementation is going off track, then build a clean, working function step by step.

What's Wrong with Your Current Code? #

Let's go through the issues one by one:

• When you use filter(lambda x:x>40,tmarks), you get a list of scores (50, 75) — but your loop uses i as an index (0-3), so checking i in get_marks is comparing an index number to a score, which will never be true.
• The condition if i in get_marks==i in zipper.values() is both syntactically and logically incorrect. This isn't how you check if a score meets your threshold.
• zipper.keys(i) is invalid syntax: a dictionary's keys() method doesn't take arguments. You can't retrieve a key by passing a value this way.

Simple, Correct Implementations #

You don't even need to convert to a dictionary to solve this — here are two straightforward approaches:

Approach 1: Iterate with Indexes

If you want to stick with using indexes, you can loop through the length of the tuples and check each score directly:

def print_students_above_40(names, marks):
    for idx in range(len(marks)):
        if marks[idx] > 40:
            print(names[idx])

# Test the function
names = ('John','Sharon','Jack','Annie')
marks = (32,50,75,12)
print_students_above_40(names, marks)

Approach 2: Use zip to Pair Names and Scores (Cleaner!)

The zip() function was made for exactly this scenario — it pairs elements from multiple iterables together. This lets you loop through names and scores directly, no indexes needed:

def print_students_above_40(names, marks):
    for name, mark in zip(names, marks):
        if mark > 40:
            print(name)

# Test the function
names = ('John','Sharon','Jack','Annie')
marks = (32,50,75,12)
print_students_above_40(names, marks)

If You Want to Use a Dictionary (Like Your Original Idea)

If you still want to use a dictionary to store student-score pairs, you can loop through the dictionary's items:

def print_students_above_40(names, marks):
    student_scores = dict(zip(names, marks))
    for name, score in student_scores.items():
        if score > 40:
            print(name)

# Test the function
names = ('John','Sharon','Jack','Annie')
marks = (32,50,75,12)
print_students_above_40(names, marks)

All three approaches will output:

Sharon
Jack

That's exactly what you're looking for!

内容的提问来源于stack exchange，提问作者Shieldbreaker