Django访问/decore_detail/路径时出现TypeError问题求解

问题场景 #

访问127.0.0.1:8000/decore_detail/123B/时，期望加载decore_detail.html页面，但运行后抛出错误：

TypeError: context must be a dict rather than set

完整报错栈 #

Traceback (most recent call last):
  File "C:\Users\daiyij\Anaconda3\envs\django\lib\site-packages\django\core\handlers\exception.py", line 55, in inner
    response = get_response(request)
  File "C:\Users\daiyij\Anaconda3\envs\django\lib\site-packages\django\core\handlers\base.py", line 197, in _get_response
    response = wrapped_callback(request, *callback_args, **callback_kwargs)
  File "D:\decoredesigner\mySite\DecoreGenerator\views.py", line 14, in decore_detail
    return render(request,'decore_detail.html',{'decore_detail',decore_detail})
  File "C:\Users\daiyij\Anaconda3\envs\django\lib\site-packages\django\shortcuts.py", line 24, in render
    content = loader.render_to_string(template_name, context, request, using=using)
  File "C:\Users\daiyij\Anaconda3\envs\django\lib\site-packages\django\template\loader.py", line 62, in render_to_string
    return template.render(context, request)
  File "C:\Users\daiyij\Anaconda3\envs\django\lib\site-packages\django\template\backends\django.py", line 57, in render
    context = make_context(
  File "C:\Users\daiyij\Anaconda3\envs\django\lib\site-packages\django\template\context.py", line 278, in make_context
    raise TypeError(

Exception Type: TypeError at /decore_detail/7520N/
Exception Value: context must be a dict rather than set.

问题原因 #

报错指向views.py第14行的render调用：

return render(request,'decore_detail.html',{'decore_detail',decore_detail})

这里用逗号分隔元素创建的是Python集合（set），但Django的render函数要求第三个参数必须是字典（dict），字典的键值对需要用冒号分隔。

另外你已经定义了正确的字典context = {"decore_detail": decore_detail}，但没有在render中使用。

解决方案 #

修改views.py代码 #

将render的第三个参数替换为正确的字典，两种方式任选：

方式一：直接使用已定义的context变量

def decore_detail(request, decore_detail):
    context = {"decore_detail": decore_detail}
    return render(request, 'decore_detail.html', context)

方式二：直接在render中传入字典

def decore_detail(request, decore_detail):
    return render(request, 'decore_detail.html', {"decore_detail": decore_detail})

额外修复urls.py的导入问题 #

你的urls.py中存在导入不一致的问题：已经从myapp.views导入了decore_detail函数，但path里却用了views.decore_detail，修改为统一的写法：

from django.contrib import admin
from myapp.views import decore_detail

urlpatterns = [
    path('admin/', admin.site.urls),
    path('decore_detail/<str:decore_detail>/', decore_detail, name='decore_detail'),
]

验证修改 #

修改完成后重新启动Django服务，访问127.0.0.1:8000/decore_detail/123B/，即可正常加载decore_detail.html页面，模板中的{{decore_detail}}会正确渲染出传入的参数值。

内容的提问来源于stack exchange，提问作者Calla