如何用正则匹配每隔一个空格？实现PHP字符串双词分组

我有这段PHP字符串：

$title1 = "Lorem Ipsum simply dummy text of the printing and typesetting industry Lorem has been the industry ";

想要把它拆成两两单词一组的数组，最终结果要像这样：

(
  [0] => "Lorem Ipsum"
  [1] => "simply dummy"
  [2] => "text of"
  [3] => "the printing"
  [4] => "and typesetting"
  [5] => "industry Lorem"
  [6] => "has been"
  [7] => "the industry"
)

试了preg_split("/ /", $title1)，但只能拆出单个单词的数组，达不到预期效果。

办法1：用正则直接匹配两两单词组合 #

直接用preg_match_all匹配连续的两个单词，还能自动处理字符串里的多余空格：

$title1 = "Lorem Ipsum simply dummy text of the printing and typesetting industry Lorem has been the industry ";
// 先去掉首尾的多余空格
$cleanStr = trim($title1);
// 匹配所有"单词+空格+单词"的组合
preg_match_all('/(\S+ \S+)/', $cleanStr, $matches);
$result = $matches[1];
// 输出来看结果
print_r($result);

运行后就能得到你要的数组。

办法2：先拆单个单词再手动分组 #

如果不想用正则，也可以先把字符串拆成单个单词的数组，再循环把每两个单词拼在一起：

$title1 = "Lorem Ipsum simply dummy text of the printing and typesetting industry Lorem has been the industry ";
// 拆分单词，同时处理多个空格的情况
$words = preg_split('/\s+/', trim($title1));
$result = [];

// 每次跳2个索引，取两个单词合并
for ($i = 0; $i < count($words); $i += 2) {
    // 防止最后只剩一个单词的情况（你的示例里是偶数个，所以这个判断可选）
    $result[] = isset($words[$i+1]) ? $words[$i] . ' ' . $words[$i+1] : $words[$i];
}

print_r($result);

这种方法逻辑更直观，方便后续调整分组规则。

内容的提问来源于stack exchange，提问作者Osman Kara