如何在Python中将包含多个字典的字符串转换为单个字典

你的输入字符串是两个JSON字典直接拼接而成，没有合法分隔符，需要先修复格式再解析合并，下面是Python实现方案：

基础方案（重复键覆盖） #

如果重复键只需要保留最后出现的值，用以下代码：

import json

# 原始输入字符串
raw_str = '{"pr2":[2,"Hair Dryer(Fashion)","₹1499.00","home/images/hairdetyerxyz.png","2"],"pr5":[1,"Bowls(Season bowls )","₹499","home/images/balls_season.png","5"]}{"pr2":[2,"Hair Dryer(Fashion)","₹1499.00","home/images/hairdetyerxyz.png","2"],"pr5":[1,"Bowls(Season bowls )","₹499","home/images/balls_season.png","5"]}'

# 修复JSON格式：将拼接的字典转为数组结构
fixed_json = '[' + raw_str.replace('}{', '},{') + ']'

# 解析为字典列表
dict_list = json.loads(fixed_json)

# 合并为单个字典
merged_dict = {}
for d in dict_list:
    merged_dict.update(d)

print(merged_dict)

进阶方案（保留重复键的所有值） #

如果需要保留所有重复键的内容，将重复值存入列表，用以下代码：

import json

raw_str = '{"pr2":[2,"Hair Dryer(Fashion)","₹1499.00","home/images/hairdetyerxyz.png","2"],"pr5":[1,"Bowls(Season bowls )","₹499","home/images/balls_season.png","5"]}{"pr2":[2,"Hair Dryer(Fashion)","₹1499.00","home/images/hairdetyerxyz.png","2"],"pr5":[1,"Bowls(Season bowls )","₹499","home/images/balls_season.png","5"]}'

fixed_json = '[' + raw_str.replace('}{', '},{') + ']'
dict_list = json.loads(fixed_json)

merged_dict = {}
for d in dict_list:
    for key, val in d.items():
        if key in merged_dict:
            # 若键已存在，将值转为列表并追加新内容
            if not isinstance(merged_dict[key], list):
                merged_dict[key] = [merged_dict[key]]
            merged_dict[key].append(val)
        else:
            merged_dict[key] = val

print(merged_dict)

内容的提问来源于stack exchange，提问作者kartik prajapati