Gradle项目中Spock Framework Where测试用例为何未单独命名？

核心原因与关键修复 #

Spock默认不会自动拆分Where子句的参数化测试用例，必须通过@Unroll注解显式开启拆分，同时配合Gradle/IntelliJ的配置来显示每个用例的详细信息。

1. 给测试方法添加@Unroll注解 #

修改测试代码，添加@Unroll并优化方法名称，让每个参数化用例的名称包含参数值：

import spock.lang.Unroll

class ArtifactoryManagerTest extends Specification {
    final static String artifact = 'artifact'
    final static String version = '1.2.3'

    @Unroll
    def "getLayoutSpecificPathHappyPath: platform #platform returns #expected"() {
        given:
        when:
        def result = artifactoryManager.getLayoutSpecificPath(platform, artifact, version)

        then:
        result == expected

        where:
        platform | expected
        'npm'    | "${artifact}/-"
        'maven'  | "${artifact}/${version}"
    }
}

注：原代码中Where子句的prefix列未在测试中使用，建议移除避免冗余。

2. 配置Gradle测试任务 #

在build.gradle（或build.gradle.kts）中添加测试日志配置，确保命令行运行时能看到每个用例的结果：

test {
    useJUnitPlatform() // 确保兼容Spock 2.x+

    testLogging {
        events 'PASSED', 'FAILED', 'SKIPPED'
        showExceptions = true
        showCauses = true
        showStackTraces = true
        displayGranularity = 2 // 显示到单个测试用例级别
        exceptionFormat = 'full'
    }
}

执行./gradlew test后，失败的用例会显示具体参数，比如：ArtifactoryManagerTest > getLayoutSpecificPathHappyPath: platform npm returns artifact/- FAILED

3. 调整IntelliJ运行设置 #

• 打开Settings → Build, Execution, Deployment → Build Tools → Gradle → Runner，勾选Delegate IDE build/run actions to Gradle，让IntelliJ使用Gradle的配置运行测试
• 在测试的Run/Debug Configuration中，进入Configuration标签页，在Test logging区域勾选Show passed tests和Show failed tests，并将Log level设为INFO

内容的提问来源于stack exchange，提问作者Peter Kahn