使用Python+Telethon向Telegram发消息报错：无法找到对应实体

我尝试用Python的Telethon库从members.csv读取聊天ID并给Telegram发送消息，但运行后报错，提示找不到ID为-100972139773的实体。

原代码 #

from telethon.sync import TelegramClient, events

import os
import random
import time

print('User-Bot started') 

api_id = api hash

api_hash = 'api id'

with TelegramClient('anonimal', api_id, api_hash) as client:
    while True:
        mem = open('C:/fg/spam/members.csv') # I take the ID of the chat from the members.csv file
-100972139773
        line = mem.readline()
        print(line)
        client.send_message(line, 'hello chat')
        print('message send')

client.run_until_disconnected()

报错信息 #

Error: Traceback (most recent call last): File
"C:\Users\drago\AppData\Local\Programs\Python\Python310\crash.py",
line 21, in
client.send_message(line, 'Сколько стоит переносной ларек?') File
"C:\Users\drago\AppData\Local\Programs\Python\Python310\lib\site-packages\telethon\sync.py",
line 39, in syncified
return loop.run_until_complete(coro) File "C:\Users\drago\AppData\Local\Programs\Python\Python310\lib\asyncio\base_events.py",
line 649, in run_until_complete
return future.result() File "C:\Users\drago\AppData\Local\Programs\Python\Python310\lib\site-packages\telethon\client\messages.py",
line 838, in send_message
entity = await self.get_input_entity(entity) File "C:\Users\drago\AppData\Local\Programs\Python\Python310\lib\site-packages\telethon\client\users.py",
line 438, in get_input_entity
await self._get_entity_from_string(peer)) File "C:\Users\drago\AppData\Local\Programs\Python\Python310\lib\site-packages\telethon\client\users.py",
line 575, in _get_entity_from_string
raise ValueError( ValueError: Cannot find any entity corresponding to "-100972139773"

问题排查与修复方案 #

1. 修正API参数赋值错误 #

代码里api_id和api_hash完全搞反了：

• api_id是Telegram开发者平台提供的数字ID，不需要加引号
• api_hash是对应的字符串哈希值，必须用引号包裹
  正确写法示例：

api_id = 1234567  # 替换成你的实际api_id数字
api_hash = 'abcdefghijklmnopqrstuvwxyz123456'  # 替换成你的实际api_hash

2. 修复文件读取的语法与逻辑错误 #

• 代码里直接插入-100972139773在代码行中，属于语法错误，必须删除
• 循环内重复打开文件会导致每次只读第一行，且readline()会带回车符\n，导致ID字符串无效，需用strip()去除首尾空白
• 用with语句管理文件，避免资源泄漏
  修改后的文件读取逻辑：

with TelegramClient('anonimal', api_id, api_hash) as client:
    # 一次性读取所有ID，避免循环重复打开文件
    with open('C:/fg/spam/members.csv', 'r') as mem:
        chat_ids = [line.strip() for line in mem if line.strip()]  # 过滤空行并去除空白
    
    for chat_id in chat_ids:
        print(chat_id)
        client.send_message(int(chat_id), 'hello chat')
        print('message sent')

3. 确保账号有权限访问目标群组/频道 #

• 个人账号必须手动加入ID为-100972139773的超级群组/频道
• Bot账号需要被该群组管理员邀请入群，并授予发消息权限，否则Telethon无法识别该实体

4. 正确转换实体ID格式 #

超级群组/频道的ID以-100开头，Telethon对整数类型的ID支持更稳定，把读取到的字符串ID转成int类型再传入send_message即可避免格式问题

5. 修复客户端运行逻辑 #

原代码中client.run_until_disconnected()写在with块外面，会导致客户端已断开后调用该方法报错，需将其放在with块内部（如果需要保持在线），或者去掉该语句（如果只是批量发消息）

最终修正后的代码示例 #

from telethon.sync import TelegramClient
import time
import random

print('User-Bot started') 

# 替换成你自己的API信息
api_id = 1234567
api_hash = 'your_api_hash_here'

with TelegramClient('anonimal', api_id, api_hash) as client:
    # 读取所有聊天ID，过滤空行
    with open('C:/fg/spam/members.csv', 'r') as mem:
        chat_ids = [line.strip() for line in mem if line.strip()]
    
    for chat_id in chat_ids:
        try:
            # 转换为整数ID并发送消息
            client.send_message(int(chat_id), 'hello chat')
            print(f'Message sent to {chat_id}')
            # 添加随机延迟，避免频繁发送触发Telegram限制
            time.sleep(random.randint(2, 5))
        except Exception as e:
            print(f'Failed to send message to {chat_id}: {str(e)}')
    
    # 如果需要保持客户端在线，取消下面的注释
    # client.run_until_disconnected()

内容的提问来源于stack exchange，提问作者Dragon Samp