如何将List<PostClass>作为参数序列化后发送至API接口？

当前运行正常的模型与代码： #

public class PostClass
{
    public string VariantName { get; set; }
    public string VariantNames { get; set; }
}

HttpWebRequest httpWebRequestContent = (HttpWebRequest)WebRequest.Create("https://localhost:44000/api/Variant/Example");

httpWebRequestContent.ContentType = "application/json";
httpWebRequestContent.Accept = "application/json";
httpWebRequestContent.PreAuthenticate = true;
httpWebRequestContent.Method = "POST";

using (StreamWriter streamWriterContent = new StreamWriter(httpWebRequestContent.GetRequestStream()))
{
    string json = JsonConvert.SerializeObject(new
                {
                    VariantName = model.VariantName,
                    VariantDetailNames = model.VariantDetailNames
                });
    streamWriterContent.Write(json);
}

需求： #

需要将List<PostClass> modelList这个列表作为参数通过序列化发送到接口。

修改方案： #

直接把modelList传入JsonConvert.SerializeObject即可，Json.NET会自动将列表序列化为标准JSON数组格式。修改后的核心代码如下：

// 请求初始化部分保持不变
HttpWebRequest httpWebRequestContent = (HttpWebRequest)WebRequest.Create("https://localhost:44000/api/Variant/Example");

httpWebRequestContent.ContentType = "application/json";
httpWebRequestContent.Accept = "application/json";
httpWebRequestContent.PreAuthenticate = true;
httpWebRequestContent.Method = "POST";

using (StreamWriter streamWriterContent = new StreamWriter(httpWebRequestContent.GetRequestStream()))
{
    // 直接序列化List<PostClass>对象
    string json = JsonConvert.SerializeObject(modelList);
    streamWriterContent.Write(json);
}

补充说明： #

如果后端接口要求参数是嵌套在某个对象中的列表（而非直接接收数组），则需要调整序列化的结构，示例如下：

string json = JsonConvert.SerializeObject(new
{
    VariantList = modelList // 属性名需与后端接口接收的参数名完全一致
});

内容的提问来源于stack exchange，提问作者Yunus Mert Çakar