Python中如何高效比较字符串列表并按指定关键词拆分生成目标列表？

我来帮你搞定这个问题！你的代码逻辑有个小疏漏：你把t_names和t_codes做了嵌套循环，这会导致每个t_codes里的元素被重复检查三次（对应t_names里的三个值），进而重复添加到两个列表中，自然得不到你想要的结果。

问题分析 #

原代码的核心问题在于：

• 每个t_codes元素会被遍历三次（每次对应一个t_names中的字符串）
• 不包含任何目标字符串的元素会被三次添加到doesnt_contain
• 包含某个目标字符串的元素，会被匹配到的那一次加入does_contain，同时被另外两次加入doesnt_contain
  最终两个列表都会出现重复和错误的元素。

正确的解决方案 #

我们应该对每个t_codes元素只检查一次，判断它是否包含t_names中的任意一个字符串，再根据结果分到对应的列表中。这里有两种实现方式：

方式1：使用子字符串匹配（更高效，适合当前场景）

因为你的需求是检查是否包含精确的子字符串，不需要正则表达式，直接用in操作符即可：

t_codes = ["11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-VM-ZRA-Operator", "11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-VM-ZRA-Admin", "11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-ZRA-User-VM-Admin", "11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-VM-ZRA-Operator", "11-XXX-Yaas-ZaaS-XXX-ZZZZ-VM-ZRA-Operator", "11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-VM-ZRA-Admin", "11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-ZRA-User-VM-Admin", "22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-VM-ZRA-Operator", "22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-VM-ZRA-Admin", "22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-ZRA-User-VM-Admin", "22-GLB-IaaS-PaaS-PROD-MSDP-CUSTOMER-IN-ZRA-User-VM-Admin", "11-XXX-Yaas-ZaaS-XXX-ZZZZ-VM-ZRA-Operator"]
t_names = ["Outsite", "NewFm", "CUSTOMER-IN"]

does_contain = []
doesnt_contain = []

for team in t_codes:
    # 判断当前元素是否包含t_names中的任意一个字符串
    has_target = any(name in team for name in t_names)
    if has_target:
        does_contain.append(team)
    else:
        doesnt_contain.append(team)

print("列表1（不包含t_names任一元素）：")
print(doesnt_contain)
print("-------------")
print("列表2（包含t_names任一元素）：")
print(does_contain)

方式2：使用正则表达式（适合需要复杂匹配的场景）

如果你后续需要更复杂的正则匹配规则，可以保留re.search，但同样用any()函数统一判断：

import re

t_codes = ["11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-VM-ZRA-Operator", "11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-VM-ZRA-Admin", "11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-ZRA-User-VM-Admin", "11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-VM-ZRA-Operator", "11-XXX-Yaas-ZaaS-XXX-ZZZZ-VM-ZRA-Operator", "11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-VM-ZRA-Admin", "11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-ZRA-User-VM-Admin", "22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-VM-ZRA-Operator", "22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-VM-ZRA-Admin", "22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-ZRA-User-VM-Admin", "22-GLB-IaaS-PaaS-PROD-MSDP-CUSTOMER-IN-ZRA-User-VM-Admin", "11-XXX-Yaas-ZaaS-XXX-ZZZZ-VM-ZRA-Operator"]
t_names = ["Outsite", "NewFm", "CUSTOMER-IN"]

does_contain = []
doesnt_contain = []

for team in t_codes:
    has_target = any(re.search(name, team) for name in t_names)
    if has_target:
        does_contain.append(team)
    else:
        doesnt_contain.append(team)

print("列表1（不包含t_names任一元素）：")
print(doesnt_contain)
print("-------------")
print("列表2（包含t_names任一元素）：")
print(does_contain)

运行结果 #

执行上述代码后，你会得到完全符合预期的两个列表：

• 列表1（不包含目标字符串）：["11-XXX-Yaas-ZaaS-XXX-ZZZZ-VM-ZRA-Operator" , "11-XXX-Yaas-ZaaS-XXX-ZZZZ-VM-ZRA-Operator"]
• 列表2（包含目标字符串）：所有包含Outsite/NewFm/CUSTOMER-IN的元素

内容的提问来源于stack exchange，提问作者kishore