如何在JavaScript的嵌套对象数组中根据bookingid搜索匹配对象？

你的问题在于原代码用了find方法，它只会返回第一个满足条件的子数组，而不是遍历所有子数组里的每一个对象，而且也没处理searchValue里的多个ID值。咱们来一步步修正，实现你要的效果：

步骤分析 #

1. 首先得把searchValue这个字符串转成数字数组，因为你的bookingid是数字类型，这样匹配的时候不会有类型不一致的问题。
2. 遍历嵌套数组里的每一个对象，检查它的bookingid是否在目标ID数组里，符合条件的就加入结果数组。

简洁实现方案（用flat+filter） #

这种方法利用数组的内置方法，代码更简洁：

let bookingArr = [
  [{ name: "user 1", bookingid: 10, product: "ab" }, { name: "user 1", bookingid: 10, product: "cd" } ],
  [{ name: "user 2", bookingid: 11, product: "ui" }, { name: "user 1", bookingid: 10, product: "ef" } ],
  [{ name: "user 3", bookingid: 12, product: "ui" }, { name: "user 4", bookingid: 13, product: "ef" } ]
];
var searchValue = "10,11";

// 把搜索字符串分割并转成数字数组
const targetBookingIds = searchValue.split(',').map(id => parseInt(id, 10));

// 先展开嵌套数组为一维，再筛选出匹配的对象
const FOUND = bookingArr.flat().filter(obj => targetBookingIds.includes(obj.bookingid));

console.log(FOUND);

直观实现方案（双重循环） #

如果你觉得内置方法不好理解，用双重循环更直观，适合新手：

let bookingArr = [
  [{ name: "user 1", bookingid: 10, product: "ab" }, { name: "user 1", bookingid: 10, product: "cd" } ],
  [{ name: "user 2", bookingid: 11, product: "ui" }, { name: "user 1", bookingid: 10, product: "ef" } ],
  [{ name: "user 3", bookingid: 12, product: "ui" }, { name: "user 4", bookingid: 13, product: "ef" } ]
];
var searchValue = "10,11";

const targetBookingIds = searchValue.split(',').map(id => parseInt(id, 10));
const FOUND = [];

// 外层循环遍历每个子数组
for (const subArray of bookingArr) {
  // 内层循环遍历子数组里的每个对象
  for (const bookingObj of subArray) {
    // 检查当前对象的bookingid是否在目标列表中
    if (targetBookingIds.includes(bookingObj.bookingid)) {
      FOUND.push(bookingObj);
    }
  }
}

console.log(FOUND);

两种方法运行后都会输出你预期的结果：

[
  { name:"user 1", bookingid:10, product: "ab" },
  { name:"user 1", bookingid:10, product: "cd" },
  { name:"user 2", bookingid:11, product: "ui" },
  { name:"user 1", bookingid:10, product: "ef" }
]

内容的提问来源于stack exchange，提问作者its me