如何在Ansible任务中覆盖队列的默认配置？

你可以通过Ansible的过滤器实现优先使用队列自身定义的配置，无定义时回退到默认配置的逻辑，修改queues.yml任务文件即可：

修改后的roles/x/tasks/queues/queues.yml #

---
- include_vars:
    file: roles/x/vars/queues.vars.yml
    name: q
- name: 创建队列
  some.module.app_queue:
    name: "{{ item.name }}"
    # 优先用当前队列的settings，不存在则加载默认配置
    settings: "{{ item.settings | default(queues.settings) }}"
    state: "{{ item.state | default('present') }}"
  loop: "{{ q.queues }}"

额外优化说明 #

1. 你的roles/x/vars/queues.vars.yml文件开头有重复的---标记，需要删除其中一个，修正后内容如下：

---
queues:
- name: queue-one
  state: present
  subscriptions:
    - projects/{{ project_id }}/topics/*/topix-1
    - projects/{{ project_id }}/topics/*/topix-2
- name: queue-two
  state: present
  subscriptions:
    - projects/{{ project_id }}/topics/*/topix-3
    - projects/{{ project_id }}/topics/*/topix-ab
- name: queue-three
  settings:
    accessType: exclusive
    egressEnabled: false
    ingressEnabled: false
    maxMsgSpoolUsage: 112
    permission: delete
  state: present
  subscriptions:
    - projects/{{ project_id }}/topics/*/topix-xy
- name: queue-four
  state: present
  subscriptions:
    - projects/{{ project_id }}/topics/*/topix-xyz
- name: queue-five
  state: present
  subscriptions:
    - projects/{{ project_id }}/topics/*/topix-123

2. 如果需要部分字段覆盖（而非全量替换默认配置），可以改用combine过滤器：

settings: "{{ queues.settings | combine(item.settings | default({})) }}"

这个写法会将默认配置与队列自定义配置合并，队列定义的字段会覆盖默认值，未定义的字段保留默认配置。

内容的提问来源于stack exchange，提问作者firefly2929