如何从包含字典的嵌套列表生成指定格式的Python字典？

To achieve your desired output, we'll iterate over each entry in your original list, create a modified version of each entry (with first_name and surname set to "anonymous"), generate a unique string key for each entry, and build the new dictionary from these key-value pairs.

Using UUIDs for Unique Keys (Recommended) #

We'll use Python's uuid module to generate globally unique random keys—this ensures no duplicates even if your original list has entries with the same id. Here's the full code:

import uuid

dict_1 = [
    {'id': '0eb7df70-f319-4562-ab2a-9e641e978b3b', 'first_name': 'Rahx', 'surname': 'Smith ', 'devices': {'os': 'Apple iPhone', 'mac_address': 'f4:af:e7:b7:ab:22', 'manufacturer': 'Apple'}, 'lat': 54.33166199876629, 'lng': -6.277842272724769, 'seenTime': 1582814754000},
    {'id': 'a0bb8d38-0d27-4d7f-acc0-1e850a706b6c', 'first_name': 'Lucy', 'surname': 'Pye', 'devices': {'os': 'Apple iPhone', 'mac_address': 'f8:87:f1:72:4c:4d', 'manufacturer': 'Apple'}, 'lat': 54.33166199876629, 'lng': -6.277842272724769, 'seenTime': 1582814754000},
    {'id': '0eb7df70-f319-4562-ab2a-9e641e978b3b', 'first_name': 'xyx', 'surname': 'dcsdd', 'devices': {'os': 'NOKIA Phone', 'mac_address': '78:28:ca:a8:56:b9', 'manufacturer': 'NOKIA'}, 'lat': 54.33166199876629, 'lng': -6.277842272724769, 'seenTime': 1582814754000},
    {'id': 'a0bb8d38-0d27-4d7f-acc0-1e850a706b6c', 'first_name': 'ddwdw', 'surname': 'sdsds', 'devices': {'os': 'MI Phone', 'mac_address': 'dc:08:0f:3f:57:0c', 'manufacturer': 'MI'}, 'lat': 54.33218267030654, 'lng': -6.27796001203896, 'seenTime': 1582814693000}
]

result_dict = {}

for entry in dict_1:
    # Create modified entry with anonymous names
    modified_entry = {
        "first_name": "anonymous",
        "surname": "anonymous",
        "lat": entry["lat"],
        "lng": entry["lng"],
        "devices": entry["devices"].copy(),  # Shallow copy to avoid altering original data
        "seenTime": entry["seenTime"]
    }
    
    # Generate unique UUID key
    unique_key = str(uuid.uuid4())
    
    # Add to result dictionary
    result_dict[unique_key] = modified_entry

# Optional: Print formatted result to verify
import json
print(json.dumps(result_dict, indent=2))

Key Notes: #

• Unique Keys: uuid.uuid4() generates random, unique identifiers that are perfect for this use case.
• Preserved Data: All original lat, lng, devices, and seenTime values are retained.
• Nested Dict Copy: We use .copy() on the devices dict to prevent accidental changes to the original dict_1 entries. If your devices dict has deeper nested structures, use copy.deepcopy() (import the copy module first).

Alternative: Index-Based Keys #

If you don't need globally unique keys and prefer simpler identifiers, use index-based keys instead:

result_dict = {}

for idx, entry in enumerate(dict_1):
    modified_entry = {
        "first_name": "anonymous",
        "surname": "anonymous",
        "lat": entry["lat"],
        "lng": entry["lng"],
        "devices": entry["devices"].copy(),
        "seenTime": entry["seenTime"]
    }
    unique_key = f"entry_{idx}"
    result_dict[unique_key] = modified_entry

内容的提问来源于stack exchange，提问作者anakin skywalker