AutoMapper能否从Dictionary<string, object>映射到派生/运行时属性类型？

AutoMapper支持从Dictionary<string, object>映射到对象图，也支持运行时多态的映射继承，但不清楚如何处理目标对象属性以基类声明，但运行时是派生实例，且要映射的属性仅存在于派生类的场景。

尝试过创建Dictionary<string, object>到基类Base和派生类Derived的映射，并用Include/IncludeAllDerived配置，但都未成功——这些配置主要针对源类型有继承层次的场景，不适用字典这种动态松散的源。

单独映射派生实例本身是正常的（调用mapper.Map(propertyImport, propertyDestination)可以成功），但当通过父对象（SomeObjectWithAProperty）映射时就会失败，因为AutoMapper只认Base的声明属性，忽略了运行时的Derived类型。

我们无法提前知道字典里的属性，也不知道哪些属性是运行时派生类型，目标是让AutoMapper根据属性的运行时类型自动映射，不受声明类型限制。

调用mapper.Map(objectImport, objectDestination)时抛出异常：

AutoMapper.AutoMapperMappingException: Error mapping types.

Mapping types:
Dictionary`2 -> SomeObjectWithAProperty
[...]
---> System.ArgumentOutOfRangeException: Cannot find member Baz of type UserQuery+Base. (Parameter 'name')

复现代码（可在LinqPad或控制台应用运行） #

void Main()
{
    var objectDestination = new SomeObjectWithAProperty
    {
        SomeProperty = new Derived(100m, 10, "bar"),
    };
    var propertyDestination = objectDestination.SomeProperty;

    var objectImport = new Dictionary<string, object>
    {
        ["SomeProperty.Foo"] = 123,
        ["SomeProperty.Bar"] = "blah",
        ["SomeProperty.Baz"] = 200m,
    };
    var propertyImport = new Dictionary<string, object>
    {
        ["Foo"] = 123,
        ["Bar"] = "blah",
        ["Baz"] = 200m,
    };

    var mapper = new MapperConfiguration(mc =>
    {
        //mc.CreateMap<Dictionary<string, object>, Base>().IncludeAllDerived();
        //mc.CreateMap<Dictionary<string, object>, Derived>();
        //mc.CreateMap<Dictionary<string, object>, Base>()
        //    .IncludeAllDerived();
        //mc.CreateMap<Dictionary<string, object>, Base>()
        //    .Include<Dictionary<string, object>, Derived>();
    }).CreateMapper();

    mapper.Map(propertyImport, propertyDestination);
    mapper.Map(objectImport, objectDestination);
}

public class SomeObjectWithAProperty
{
    public Base SomeProperty { get; set; }
}

public record Base(int Foo, string Bar);
public record Derived(decimal Baz, int Foo, string Bar) : Base(Foo, Bar);

内容的提问来源于stack exchange，提问作者MicrosoftStackDev