开发文本类房间收集物品游戏遇TypeError: unhashable type: 'dict'求助

错误信息 #

player_move in rooms[currentRoom]:
TypeError: unhashable type: 'dict'

用户代码 #

rooms = {
        'Laundry Room': {'West': 'Basement'}, #Game Starts Here
        'Basement': {'North': 'Kitchen'},
        'Kitchen': {'West': 'Living Room', 'East': 'Dining Room', 'North': 'Bedroom', 'South': 'Basement'},
        'Living Room': {'East': 'Kitchen', 'item': '$100 cash'},
        'Dining Room': {'West': 'Kitchen', 'North': 'Backyard', 'item': '$6 cash'},
        'Bedroom': {'South': 'Kitchen', 'East': 'Bathroom', 'item': '$200 cash'},
        'Bathroom': {'West': 'Bedroom', 'item': '$300 cash'},
        'Backyard': {'South': 'Dining Room', 'item': '$60 cash'} #Return to the Laundry Room via the Basement
}

player_move = ['North', 'South', 'East', 'West']
currentRoom = rooms['Laundry Room']

# While Loop for moving between rooms
while True:


    player_move = input('Enter a move: \n')

    if player_move == 'Exit':
        print('Thanks for playing.')
        # break statement for exiting
        break

    if player_move in rooms[currentRoom]:
        currentRoom = rooms[currentRoom][player_move]

        addItem = input(' \n')

        if 'item' in rooms[currentRoom]:
            game(rooms[currentRoom]['item'])

问题根源 #

错误出在currentRoom的赋值和使用逻辑上：

• 初始时currentRoom = rooms['Laundry Room']，这把currentRoom变成了一个字典（比如{'West': 'Basement'}）
• 而rooms字典的键是字符串类型的房间名（比如'Laundry Room'），当你执行rooms[currentRoom]时，相当于用一个字典当键去访问另一个字典，字典是不可哈希的类型，所以抛出TypeError: unhashable type: 'dict'

修复方案 #

1. 修正currentRoom的初始值 #

把currentRoom改成存储房间名字符串，而不是房间字典：

currentRoom = 'Laundry Room'  # 存房间名，不是房间字典

2. 调整后续代码的访问逻辑 #

所有需要获取当前房间信息的地方，用rooms[currentRoom]来访问对应的字典：

while True:
    player_move = input('Enter a move: \n')

    if player_move == 'Exit':
        print('Thanks for playing.')
        break

    # 检查当前房间是否有该方向的出口
    if player_move in rooms[currentRoom]:
        # 更新currentRoom为目标房间的名字
        currentRoom = rooms[currentRoom][player_move]

        # 补充物品收集的交互提示
        addItem = input('是否收集当前房间的物品？(Y/N)\n')

        # 检查当前房间是否有物品
        if 'item' in rooms[currentRoom]:
            # 替换未定义的game函数，补充实际收集逻辑
            print(f"你收集到了{rooms[currentRoom]['item']}")
            # 可移除物品避免重复收集
            # del rooms[currentRoom]['item']

3. 其他小问题修复 #

• 变量名冲突：初始的player_move是列表，后来被赋值为输入字符串，建议重命名初始列表为valid_moves避免混淆
• game函数未定义：需要补充物品收集的具体逻辑，比如定义玩家背包列表，收集时添加进去

完整修复后的示例代码 #

rooms = {
        'Laundry Room': {'West': 'Basement'}, #Game Starts Here
        'Basement': {'North': 'Kitchen'},
        'Kitchen': {'West': 'Living Room', 'East': 'Dining Room', 'North': 'Bedroom', 'South': 'Basement'},
        'Living Room': {'East': 'Kitchen', 'item': '$100 cash'},
        'Dining Room': {'West': 'Kitchen', 'North': 'Backyard', 'item': '$6 cash'},
        'Bedroom': {'South': 'Kitchen', 'East': 'Bathroom', 'item': '$200 cash'},
        'Bathroom': {'West': 'Bedroom', 'item': '$300 cash'},
        'Backyard': {'South': 'Dining Room', 'item': '$60 cash'} #Return to the Laundry Room via the Basement
}

valid_moves = ['North', 'South', 'East', 'West']
currentRoom = 'Laundry Room'
player_inventory = []

# 定义收集物品的函数
def collect_item(item):
    player_inventory.append(item)
    print(f"你获得了{item}！当前背包：{player_inventory}")

# While Loop for moving between rooms
while True:
    # 显示当前房间信息
    print(f"\n当前房间：{currentRoom}")
    if 'item' in rooms[currentRoom]:
        print(f"房间里有：{rooms[currentRoom]['item']}")
    
    player_move = input('输入移动方向（North/South/East/West）或Exit退出：\n')

    if player_move == 'Exit':
        print('Thanks for playing.')
        break

    # 检查输入的方向是否有效
    if player_move in valid_moves:
        # 检查当前房间是否有该出口
        if player_move in rooms[currentRoom]:
            currentRoom = rooms[currentRoom][player_move]
            # 检查新房间是否有物品
            if 'item' in rooms[currentRoom]:
                choice = input(f"发现物品{rooms[currentRoom]['item']}，是否收集？(Y/N)\n").strip().upper()
                if choice == 'Y':
                    collect_item(rooms[currentRoom]['item'])
                    # 移除物品，防止重复收集
                    del rooms[currentRoom]['item']
        else:
            print('那个方向没有门！')
    else:
        print('无效输入，请输入正确的方向或Exit！')

内容的提问来源于stack exchange，提问作者user22582701