如何在Matplotlib中高亮指定X轴标签(如STRIKES的350)
如何将Matplotlib图表中指定X轴标签设置为自定义颜色和字号?
问题背景
我有如下Pandas DataFrame数据:
import pandas as pd data = {'PEOI': [190, 105, 100, 150, 100, 170], 'PCHOI': [11, 6, 3, 16, 21, 8], 'STKS': [200, 250, 300, 350, 400, 450], 'CCHOI': [3, 8, 13, 18, 3, 23], 'CEOI': [154, 190, 578, 611, 736, 420]} df = pd.DataFrame(data) print(df)
我使用以下Matplotlib代码绘图:
import matplotlib.pyplot as plt plt.style.use("dark_background") fig, axes = plt.subplots(2, 1, figsize=(17,15)) for (y1, y2), ax in zip([("CEOI", "PEOI"), ("CCHOI", "PCHOI")], axes): ax.bar(df["STKS"], df[y1], width=13, label=y1,color = 'blue') ax.bar(df["STKS"], df[y2], width=7, label=y2,color = 'yellow') ax.set_xlabel("STRIKES", fontsize=24, fontweight="bold", labelpad=10, color ='cyan') ax.set_ylabel("OPEN INTEREST", fontweight="bold", fontsize=24, labelpad=10) ax.set_xticks(df["STKS"].values) ax.tick_params(labelsize=20) ax.tick_params(axis="x", rotation=90) ax.legend(fontsize=18) if y1 == "CEOI": ax.set_title("OPEN INTEREST",fontsize=26,fontweight="bold", loc="left", color ='yellow') elif y1 == "CCHOI": ax.set_title("CHANGE IN OPEN INTEREST",fontsize=24,fontweight="bold", loc="left", color ='yellow') ax.grid(axis="y", linestyle=(0, (15, 8)), alpha=0.4) ax.set_axisbelow(True) for p in ax.patches: ax.annotate(format(p.get_height(), '.0f'), (p.get_x() + p.get_width() / 2., p.get_height()), ha='center', va='center', xytext=(1.5, 4), textcoords='offset points', fontsize=16, fontweight="bold") fig.tight_layout() plt.show(block=True)
需要实现:将指定X轴标签(例如STRIKES中的350)设置为自定义颜色和字号,该如何操作?
解决方案
要单独修改某个X轴标签的样式,可通过以下步骤实现:
- 设置完
ax.set_xticks()后,获取所有X轴刻度标签对象 - 遍历标签列表,匹配目标刻度值对应的标签
- 为匹配到的标签设置自定义颜色、字号等属性
修改后的完整代码(以将350标签设置为红色、字号28、加粗为例):
import pandas as pd import matplotlib.pyplot as plt data = {'PEOI': [190, 105, 100, 150, 100, 170], 'PCHOI': [11, 6, 3, 16, 21, 8], 'STKS': [200, 250, 300, 350, 400, 450], 'CCHOI': [3, 8, 13, 18, 3, 23], 'CEOI': [154, 190, 578, 611, 736, 420]} df = pd.DataFrame(data) plt.style.use("dark_background") fig, axes = plt.subplots(2, 1, figsize=(17,15)) target_strike = 350 # 要修改的目标STRIKES值 for (y1, y2), ax in zip([("CEOI", "PEOI"), ("CCHOI", "PCHOI")], axes): ax.bar(df["STKS"], df[y1], width=13, label=y1,color = 'blue') ax.bar(df["STKS"], df[y2], width=7, label=y2,color = 'yellow') ax.set_xlabel("STRIKES", fontsize=24, fontweight="bold", labelpad=10, color ='cyan') ax.set_ylabel("OPEN INTEREST", fontweight="bold", fontsize=24, labelpad=10) ax.set_xticks(df["STKS"].values) # 获取X轴刻度标签并修改目标标签样式 xtick_labels = ax.get_xticklabels() for label in xtick_labels: if int(label.get_text()) == target_strike: label.set_color('red') label.set_fontsize(28) label.set_fontweight('bold') ax.tick_params(labelsize=20) ax.tick_params(axis="x", rotation=90) ax.legend(fontsize=18) if y1 == "CEOI": ax.set_title("OPEN INTEREST",fontsize=26,fontweight="bold", loc="left", color ='yellow') elif y1 == "CCHOI": ax.set_title("CHANGE IN OPEN INTEREST",fontsize=24,fontweight="bold", loc="left", color ='yellow') ax.grid(axis="y", linestyle=(0, (15, 8)), alpha=0.4) ax.set_axisbelow(True) for p in ax.patches: ax.annotate(format(p.get_height(), '.0f'), (p.get_x() + p.get_width() / 2., p.get_height()), ha='center', va='center', xytext=(1.5, 4), textcoords='offset points', fontsize=16, fontweight="bold") fig.tight_layout() plt.show(block=True)
关键说明
- 提前定义
target_strike变量,方便后续修改目标刻度值 - 每个X轴标签是
Text类型对象,支持set_color()、set_fontsize()、set_fontweight()等样式修改方法 - 需将标签文本转为整数后与目标值比较,因为标签默认以字符串形式存储
内容的提问来源于stack exchange,提问作者Brijesh Chaurasia
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