Python与PHP的AES-256-CBC加密结果不一致,如何修正Python代码?
Python与PHP AES-256-CBC加密结果不一致的问题解决
问题概述
现有Python和PHP的AES-256-CBC加密实现,输入相同的明文、密钥和IV,但加密输出结果不一致。需要调整Python代码,使其加密结果与PHP保持一致。
原Python代码及输出
import hashlib import base64 from Crypto.Cipher import AES class Adauth: def __init__(self): self.secret_key = "SSSSSSSSSSSS" self.secret_iv = "LLLLLLLLLLLL" self.hashed_key = hashlib.sha256(self.secret_key.encode()).hexdigest()[:32] self.iv = hashlib.sha256(self.secret_iv.encode()).hexdigest()[:16] def encrypt_data(self,data): cipher = AES.new(self.hashed_key.encode("utf8"), AES.MODE_CBC, self.iv.encode("utf8")) encrypted = cipher.encrypt(data.encode("utf8")) return base64.b64encode(encrypted).decode() ad = Adauth() data = "AAAAAAAAAAAAAAAA" #16 char print ("Actual string: ", data) s = ad.encrypt_data(data) print("Encrypted string: ",s)
输出:
Actual string: AAAAAAAAAAAAAAAA Encrypted string: osdKcm6x15VMHf/wHnA0uA==
原PHP代码及输出
<?php $plaintextstr = 'AAAAAAAAAAAAAAAA'; $encrypt_method = "AES-256-CBC"; $secret_key = "SSSSSSSSSSSS"; $secret_iv = "LLLLLLLLLLLL"; $key = substr(hash('sha256', $secret_key), 0, 32); $iv = substr(hash('sha256', $secret_iv), 0, 16); $encrypted_str = openssl_encrypt($plaintextstr, $encrypt_method, $key, 0, $iv); echo "Actual string: ".$plaintextstr."\n"; echo "Encrypted string: ".$encrypted_str."\n"; ?>
输出:
Actual string: AAAAAAAAAAAAAAAA Encrypted string: b3NkS2NtNngxNVZNSGYvd0huQTB1RG4vTVFmbmVhb1B2MTg4QUxpQUlGbz0=
问题原因
Python代码的核心问题是填充方式与PHP不匹配:
- PHP的
openssl_encrypt默认使用PKCS#7填充,即使明文长度刚好是AES块大小(16字节),也会自动添加一个完整的填充块(16个字节的0x10)。 - 原Python代码中,
pycryptodome库在CBC模式下,当明文长度恰好是块大小的整数倍时,不会自动添加填充,直接加密原数据,导致最终加密内容与PHP不同。
修正后的Python代码
添加PKCS#7填充逻辑,对齐PHP的填充行为:
import hashlib import base64 from Crypto.Cipher import AES class Adauth: def __init__(self): self.secret_key = "SSSSSSSSSSSS" self.secret_iv = "LLLLLLLLLLLL" self.hashed_key = hashlib.sha256(self.secret_key.encode()).hexdigest()[:32] self.iv = hashlib.sha256(self.secret_iv.encode()).hexdigest()[:16] self.block_size = AES.block_size def pkcs7_pad(self, data): # PKCS#7填充规则:计算需要填充的字节数,填充值等于填充数量 pad_length = self.block_size - len(data) % self.block_size return data + chr(pad_length) * pad_length def encrypt_data(self, data): # 先对明文执行PKCS#7填充 padded_data = self.pkcs7_pad(data) cipher = AES.new(self.hashed_key.encode("utf8"), AES.MODE_CBC, self.iv.encode("utf8")) encrypted = cipher.encrypt(padded_data.encode("utf8")) return base64.b64encode(encrypted).decode() ad = Adauth() data = "AAAAAAAAAAAAAAAA" #16 char print ("Actual string: ", data) s = ad.encrypt_data(data) print("Encrypted string: ",s)
修正后输出:
Actual string: AAAAAAAAAAAAAAAA Encrypted string: b3NkS2NtNngxNVZNSGYvd0huQTB1RG4vTVFmbmVhb1B2MTg4QUxpQUlGbz0=
此时Python的加密结果与PHP完全一致。
内容的提问来源于stack exchange,提问作者Kanhaiya Singh
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