Python Hangman代码修改：实现首次正确猜词提示与重复输入处理

需求说明 #

• 用户首次猜中正确字母时，在显示单词的下方输出提示：Congrats, You have chosen the right letter!
• 重复输入已猜过的字母时，仅输出：You have already chosen this letter，不显示祝贺文本

修改后的完整代码 #

import random
from replit import clear
from hangman_art import logo, stages
print(logo)
print("\nWelcome to Lucid's Hangman!")

from hangman_words import word_list

choice = random.choice(word_list)
# 测试用：可以注释掉下面这行，正式运行时隐藏答案
print(choice)

lives = 6
running = True

display = []
for letter in choice:
    display += "_"
# 新增列表记录所有已猜过的字母
guessed_letters = []

while running:
    guess = input("Guess a letter: ").lower()
    clear()
    
    # 先判断是否重复猜过字母
    if guess in guessed_letters:
        print("You have already chosen this letter")
    else:
        guessed_letters.append(guess)
        # 标记是否首次猜中正确字母
        correct_guess = False
        for position in range(len(choice)):
            letter = choice[position]
            if letter == guess:
                display[position] = letter
                correct_guess = True
        
        print(display)
        
        if correct_guess:
            # 首次猜中时输出祝贺
            print("Congrats, You have chosen the right letter!")
        else:
            # 猜错时扣减生命
            lives -= 1
            print("You have chosen a wrong letter. You lose a life")
            if lives == 0:
                running = False
                print("You lose!")
    
    # 检查是否获胜
    if "_" not in display:
        running = False
        print("You have won!")
    
    print(stages[lives])

修改说明 #

1. 新增guessed_letters列表：专门记录所有已经输入过的字母，清晰区分重复猜字母的情况，避免和display列表的判断混淆
2. 调整逻辑顺序：先判断是否重复猜字母，再处理猜中/猜错的业务逻辑，流程更清晰
3. 首次猜中判断：用correct_guess标记位，只有当字母是首次猜中且正确时，才输出祝贺文本
4. 修正猜错判断逻辑：原代码中guess not in display的判断会把重复猜正确字母误判为猜错，现在通过correct_guess标记位准确判断猜错场景

内容的提问来源于stack exchange，提问作者LucidKoder