Node.js调用Google Places API遇language_code无效错误求助

我尝试编写脚本调用新版Google Places API，curl请求能正常运行：

curl -X POST -d '{
  "textQuery" : "101 Gowrie, Amsterdam"
}' \
-H 'Content-Type: application/json' -H 'X-Goog-Api-Key: ...' \
-H 'X-Goog-FieldMask: places.displayName,places.formattedAddress' \
'https://places.googleapis.com/v1/places:searchText'

但Node.js的fetch请求却返回错误：

fetch("https://places.googleapis.com/v1/places:searchText", {
  method: "POST",
  body: JSON.stringify({ textQuery: "101 Gowrie, Amsterdam" }),
  headers: {
    "Content-Type": "application/json",
    "X-Goog-Api-Key": apiKey,
    "X-Goog-FieldMask": "places.displayName,places.formattedAddress"
  }
}).then(res => res.json()).then(console.log).catch(console.log)

错误信息：

{
  "error": {
    "code": 400,
    "message": "Invalid language_code: '*'. See full list of supported languages at https://developers.google.com/maps/faq#languagesupport.\n",
    "status": "INVALID_ARGUMENT"
  }
}

我从未设置过*作为语言代码，想要获取英文结果，对此感到困惑。

这个问题是因为Node.js环境中，fetch会默认传递带通配符*的Accept-Language请求头，新版Google Places API会将该值解析为language_code参数，触发验证失败。

可以通过两种方式解决：

• 显式指定请求体的languageCode字段：在POST的JSON body中添加languageCode参数，设置为目标语言（比如英文用"en"），覆盖默认行为：

fetch("https://places.googleapis.com/v1/places:searchText", {
  method: "POST",
  body: JSON.stringify({ 
    textQuery: "101 Gowrie, Amsterdam",
    languageCode: "en"
  }),
  headers: {
    "Content-Type": "application/json",
    "X-Goog-Api-Key": apiKey,
    "X-Goog-FieldMask": "places.displayName,places.formattedAddress"
  }
}).then(res => res.json()).then(console.log).catch(console.log)

• 添加Accept-Language请求头：在headers中设置明确的语言值，替换默认的通配符：

fetch("https://places.googleapis.com/v1/places:searchText", {
  method: "POST",
  body: JSON.stringify({ textQuery: "101 Gowrie, Amsterdam" }),
  headers: {
    "Content-Type": "application/json",
    "X-Goog-Api-Key": apiKey,
    "X-Goog-FieldMask": "places.displayName,places.formattedAddress",
    "Accept-Language": "en"
  }
}).then(res => res.json()).then(console.log).catch(console.log)

两种方法都能让API正确识别目标语言，避免解析出无效的*值。

内容的提问来源于stack exchange，提问作者Simon H