嵌套while循环逻辑异常排查：电影票价程序退出问题

我正在练习while循环及通用循环编程技巧，遇到了一个问题。我尝试编写一个根据用户年龄计算电影票价的程序：外层循环和第一个输入语句处理年龄转票价的逻辑。用户输入年龄并得到对应票价后，外层循环中的内层循环会通过第二个输入询问是否有其他同行人员，预期逻辑如下：

• 若用户回答'no'，整个程序终止
• 若回答'yes'，仅内层循环终止，外层循环重新执行
• 若输入非'yes'/'no'，内层循环重新执行

但实际运行时，在内层循环输入'no'时，仅内层循环终止，外层循环会重新启动，无法实现整个程序退出的预期效果。

初始代码 #

while True:
    
    age = input("Enter your age and the price of the movie will be displayed: ")
    if age == 'quit':
        break
    elif int(age) < 3:
        print("You're ticket price today is free.")
       
    elif int(age) < 12:
        print("You're ticket price today is $10. ")
    elif int(age) <= 150:
        print("You're ticket price today is $15")
    elif int(age) > 150:
        print("You've entered an invalid input. Please enter a valid age or type 'quit' to exit.")
    else:
        print("You've entered an invalid input. Please enter a valid age or type 'quit' to exit.")
        
    while True:
        repeat = input("Do you have someone else who's attending this movie? (yes/no): ")
        if repeat.lower() == 'no':
            break
        elif repeat.lower() == 'yes':
            break
        else:
            print("You've entered an invalid input. Please enter 'yes' to add someone or 'no' to quit.")

优化尝试代码（更新2） #

flag = True
while flag:   

  
    while True:
        
        age = input("Enter your age and the price of the movie will be displayed: ")
        if age == 'quit':
            break
        elif int(age) < 3:
            print("You're ticket price today is free.")
           
        elif int(age) < 12:
            print("You're ticket price today is $10. ")
        elif int(age) <= 150:
            print("You're ticket price today is $15")
        elif int(age) > 150:
            print("You've entered an invalid input. Please enter a valid age or type 'quit' to exit.")
        else:
            print("You've entered an invalid input. Please enter a valid age or type 'quit' to exit.")
        
        
        while True:
            repeat = input("Do you have someone else who's attending this movie? (yes/no): ")
            if repeat.lower() == 'no':
                flag = False 
                break
            elif repeat.lower() == 'yes':
                break
            else:
                print("You've entered an invalid input. Please enter 'yes' to add someone or 'no' to quit.")

内容的提问来源于stack exchange，提问作者EM284