discord.py RuntimeWarning：协程未被等待问题求助（附相关代码）

问题代码 #

发送初始消息 #

embed = discord.Embed(title="**hi**", color=discord.Color.green())
embed.add_field(name="", value=f"(**hello**)", inline=False)
Origin_embed = await interaction.response.send_message(embed=embed, ephemeral=False)

支付检查处理函数 #

async def perform_toss_check_pay(name, amount, interaction: discord.Interaction, random_name, Origin_embed):
    res = toss.check(name.strip(), amount)
    print(res)
    if res.get('result') == True:
        MSG = res.get('msg')
        embed = discord.Embed(title="**``✅`` ┃ checked**", color=discord.Color.green())
        await interaction.response.send_message(embed=embed, ephemeral=False)
        Interaction.delete_original_response(Origin_embed)
    if res.get('msg') == '입금 미확인':
        Interaction.delete_original_response(Origin_embed)

触发的警告 #

RuntimeWarning: coroutine 'Interaction.delete_original_response' was never awaited
Interaction.delete_original_response(Origin_embed)
RuntimeWarning: Enable tracemalloc to get the object allocation traceback.

试过的无效写法 #

await Interaction.delete_original_response(Origin_embed)
Interaction.delete_original_response(await Origin_embed)
Interaction.delete_original_response.Origin_embed

问题原因及修复方案 #

几个关键错误 #

1. 异步方法未加await：delete_original_response是异步协程方法，必须用await关键字触发执行，否则只会生成未执行的协程对象，触发警告。
2. 调用方式错误：直接用Interaction类调用方法是错误的，应该使用函数参数里的interaction实例来调用该方法。
3. 重复响应交互：处理函数中再次调用interaction.response.send_message会报错——一个交互只能用response.send_message响应一次，后续消息必须用followup.send发送。
4. 参数传递错误：delete_original_response是实例方法，不需要传入Origin_embed；或者直接用Origin_embed（这是Message对象）调用delete()方法更直观。

修复后的代码 #

async def perform_toss_check_pay(name, amount, interaction: discord.Interaction, random_name, Origin_embed):
    res = toss.check(name.strip(), amount)
    print(res)
    if res.get('result') == True:
        MSG = res.get('msg')
        embed = discord.Embed(title="**``✅`` ┃ checked**", color=discord.Color.green())
        # 用followup发送后续消息，避免重复响应交互
        await interaction.followup.send(embed=embed, ephemeral=False)
        # 方案1：通过interaction实例删除原响应
        await interaction.delete_original_response()
        # 方案2：直接删除返回的Message对象（二选一即可）
        # await Origin_embed.delete()
    if res.get('msg') == '입금 미확인':
        # 二选一即可
        await interaction.delete_original_response()
        # await Origin_embed.delete()

内容的提问来源于stack exchange，提问作者Jimin Sung