Kotlin中打印返回String类型的函数时多余$符号的解决方法

你遇到的问题是因为在showProfile函数的println语句里，多写了一个转义的\$符号，这个符号会被直接输出到结果里。只需要把这个多余的\$删掉就能解决问题。

修正后的代码如下：

fun main() {    
    val amanda = Person("Amanda", 33, "play tennis", null)
    val atiqah = Person("Atiqah", 28, "climb", amanda)
    
    amanda.showProfile()
    atiqah.showProfile()
}

class Person(val name: String, val age: Int, val hobby: String?, val referrer: Person?) {
    fun showProfile() {
        fun reference(referrer: Person?): String {
            return if(referrer!=null) "Has a referrer named ${referrer.name}, who likes to ${referrer.hobby}." else "Doesn't have a referrer.\n"
        }
        // 移除了多余的\$符号
        println("Name: $name\nAge: $age\nLikes to $hobby. ${reference(referrer)}")
    }
}

修改后运行代码，就能得到你预期的输出：

Name: Amanda
Age: 33
Likes to play tennis. Doesn't have a referrer.

Name: Atiqah
Age: 28
Likes to climb. Has a referrer named Amanda, who likes to play tennis.

内容的提问来源于stack exchange，提问作者Vinay Mhatre