Python调用displayRent()出现NameError未定义错误求助

错误根源分析 #

• 调用getType()时未接收返回的choice和furnished变量，导致这两个值在全局作用域中未定义，直接传入displayRent()触发NameError。
• displayRent()调用时参数顺序与函数定义完全不符，函数定义顺序为choice, furnished, deposit, rent，但调用时传参顺序颠倒。
• 缺少调用determineRent()的步骤，未生成deposit和rent变量，这两个值同样未定义。
• 选择退出（选项4）后未终止程序，会继续执行后续输入逻辑，引发不必要的错误。

修复后的完整代码 #

# 显示公寓类型菜单
def menu():
    print("""
    Type of Apartments for rent

          1) Studio
          2) One Bedroom
          3) Two Bedroom
          4) EXIT PROGRAM
          """)

# 获取用户选择的公寓类型及是否需要家具
def getType():
    choicelist = [1,2,3,4]
    choice = int(input("Enter the apartment type you wish to rent (1-3 or 4 to EXIT PROGRAM): "))
    
    # 验证输入合法性
    while choice not in choicelist:
        print("ERROR: Invalid apartment type...MUST be 1-4!")
        choice = int(input("Enter the apartment type you wish to rent (1-3 or 4 to EXIT PROGRAM): "))
    
    if choice == 4:  
        print("""EXITING THE PROGRAM...
Thanks for inquiring about our apartments for rent!""")
        return None, None  # 返回空值标记退出
    
    furnished = input("Do you want the apartment furnished (Y/N)? ").upper()
    # 验证家具选择合法性
    while furnished not in ['Y', 'N']:
        print("ERROR: Invalid input...MUST be Y or N!")
        furnished = input("Do you want the apartment furnished (Y/N)? ").upper()
    
    return choice, furnished

# 根据选择计算租金和押金
def determineRent(choice, furnished):
    deposits = [0, 800, 1000, 1200]
    unfurnished = [0, 1200, 1500, 1800]
    Furnished_ = [0, 1500, 1800, 2050]

    deposit = deposits[choice]
    rent = Furnished_[choice] if furnished == 'Y' else unfurnished[choice]

    return deposit, rent

# 显示租金和押金信息
def displayRent(choice, furnished, deposit, rent):
    description = ["", "Studio", "One-Bedroom", "Two-Bedroom"]
    print("Description:", description[choice], "Furnished" if furnished == "Y" else "Unfurnished")
    print(f"Deposit: ${deposit}")
    print(f"Rent: ${rent}")
    print()

# 主程序逻辑
menu()
choice, furnished = getType()

# 判断是否退出程序
if choice is not None:
    deposit, rent = determineRent(choice, furnished)
    displayRent(choice, furnished, deposit, rent)

关键修复点说明 #

1. 接收getType()的返回值：用choice, furnished = getType()获取用户输入的变量，确保这些值在后续逻辑中可用。
2. 修正displayRent()传参顺序：按照函数定义的顺序传入参数，保证逻辑对应。
3. 添加退出判断：当用户选择4时，getType()返回None, None，主程序判断后跳过后续计算和显示逻辑，直接结束。
4. 新增家具输入验证：避免用户输入非Y/N的非法值，增强程序健壮性。
5. 简化字符串格式化：使用f-string替代format()，让代码更简洁易读。

内容的提问来源于stack exchange，提问作者Nicole Greenen