如何在WordPress中仅显示自定义文章类型newsroom关联的分类法类型

要只显示自定义文章类型「newsroom」关联的「types」分类术语，你需要修改get_terms的参数，限定仅返回与newsroom文章绑定的分类项，具体修改如下：

修改后的完整代码 #

<form action="<?php echo site_url() ?>/wp-admin/admin-ajax.php" method="POST" id="filter">
    <input type="hidden" name="action" value="resource_filter">
    <?php
        // 获取所有newsroom类型文章的ID数组
        $newsroom_post_ids = get_posts(array(
            'post_type' => 'newsroom',
            'posts_per_page' => -1,
            'fields' => 'ids' // 仅获取ID字段，提升性能
        ));

        // 仅获取与newsroom文章关联的types分类术语
        if( $terms = get_terms( array( 
            'taxonomy' => 'types', 
            'orderby' => 'name',
            'object_ids' => $newsroom_post_ids, // 限定关联的文章范围
            'hide_empty' => false // 若需隐藏无关联文章的术语，可改为true
        ) ) ) {
            ?> <div class="types-filter"><h3>Types</h3> <?php
          foreach ( $terms as $term ){ ?>
            <label class="MuiFormControlLabel-root">
                <span class="MuiButtonBase-root MuiIconButton-root jss317 MuiCheckbox-root MuiCheckbox-colorSecondary MuiIconButton-colorSecondary" aria-disabled="false">
                    <span class="MuiIconButton-label">
                    <input type="checkbox" name="types_filter[]" id="checkbox_types_filter_<?php echo $term->term_id; ?>" class="resource-filter-checkbox" value="<?php echo $term->term_id; ?>" data-indeterminate="false" data_term_name="<?php echo $term->name; ?>">
                    </span>
                </span>
                <span class="MuiTypography-root MuiFormControlLabel-label MuiTypography-body1">
                    <p class="MuiTypography-root MuiTypography-body2"><?php echo $term->name; ?></p>
                </span>
            </label>
          <?php 
            }
          ?> 
          </div> 
    <?php
        } ?>
 </form>

关键修改说明 #

1. 先通过get_posts获取所有newsroom类型文章的ID，仅提取ID字段减少资源消耗
2. 在get_terms参数中添加object_ids，传入上述ID数组，让分类术语仅筛选与这些文章关联的项
3. hide_empty参数可按需调整：设为true会隐藏当前无关联newsroom文章的术语，设为false则保留所有曾关联过的术语

内容的提问来源于stack exchange，提问作者Justin