如何用MLT替代地理纬度绘制南极上空MLAT-MLT能量分布极图?
MATLAB 实现方案
问题核心是把地理坐标的海岸线转换为MLAT-MLT坐标,再在适配的坐标网格上绘图,而非依赖地理投影的worldmap。
关键步骤
1. 安装地磁坐标转换工具
MATLAB无内置MLAT-MLT转换,需借助第三方工具包,比如从MathWorks File Exchange下载的igrf工具包,或Space Physics Toolbox (SPT)。以SPT为例,先添加路径:
addpath('path/to/SPT');
2. 转换海岸线至MLAT-MLT坐标
MLT依赖观测时间,需与你的数据时间匹配,假设时间为obs_time = datetime('2023-01-01 12:00:00'):
load coastlines % 筛选南极区域海岸线(纬度<-40) south_idx = coastlat < -40; clat = coastlat(south_idx); clon = coastlon(south_idx); % 地理坐标转地磁坐标 [mlat_coast, mlt_coast] = geo2mag(clat, clon, obs_time);
3. 绘制MLAT-MLT极坐标图
all_data = load('struct.mat'); all_data = all_data.struct; lat = all_data.lat; mlt = all_data.mlt; heat = all_data.heat; figure('Position', [100 100 800 800]) ax = polaraxes; % MLT转弧度,MLAT转半径(-90对应0,-40对应50) theta = mlt * 2*pi/24; r = 90 + lat; scatter(theta, r, 75, heat, 'filled', 's'); % 叠加转换后的海岸线 theta_coast = mlt_coast * 2*pi/24; r_coast = 90 + mlat_coast; plot(theta_coast, r_coast, 'k', 'LineWidth', 1); % 美化设置 ax.ThetaDir = 'clockwise'; % MLT顺时针递增 ax.ThetaZeroLocation = 'top'; % 0MLAT置于顶部 ax.RTick = [10 30 50]; ax.RTickLabel = {'-80', '-60', '-40'}; ax.ThetaTick = 0:3:24; ax.ThetaTickLabel = {'0', '3', '6', '9', '12', '15', '18', '21', '24'}; colormap('parula') caxis([0 40000]) colorbar; title('南极离子能量分布 (MLAT vs MLT)');
Python 实现方案
Python用pyspedas做地磁转换,matplotlib绘图,灵活性更强。
关键步骤
1. 安装依赖
pip install pyspedas matplotlib cartopy
2. 代码实现
import numpy as np import matplotlib.pyplot as plt from pyspedas import geomag import cartopy.feature as cfeature from cartopy.io.shapereader import Reader # 加载数据 all_data = np.load('struct.mat', allow_pickle=True)['struct'].item() lat = all_data['lat'] mlt = all_data['mlt'] heat = all_data['heat'] # 匹配数据的观测时间 obs_time = '2023-01-01 12:00:00' # 转换南极海岸线至MLAT-MLT land_feature = cfeature.NaturalEarthFeature('physical', 'land', '110m', edgecolor='black', facecolor='none') reader = Reader(land_feature.path) mlat_coast = [] mlt_coast = [] for geom in reader.geometries(): for polygon in geom.geoms: coords = np.array(polygon.exterior.coords) clon, clat = coords[:, 0], coords[:, 1] south_idx = clat < -40 if np.any(south_idx): # 地理坐标转地磁坐标 mlat, _, mlt_val = geomag.geomag(clat[south_idx], clon[south_idx], obs_time, 'geo', 'mag') mlat_coast.extend(mlat) mlt_coast.extend(mlt_val) # 转换为极坐标格式 theta = np.deg2rad(mlt * 15) r = 90 + lat theta_coast = np.deg2rad(np.array(mlt_coast) * 15) r_coast = 90 + np.array(mlat_coast) # 绘图 fig = plt.figure(figsize=(8, 8)) ax = fig.add_subplot(111, polar=True) sc = ax.scatter(theta, r, c=heat, s=75, marker='s', cmap='viridis', vmin=0, vmax=40000) ax.plot(theta_coast, r_coast, 'k', linewidth=1) # 美化设置 ax.set_theta_direction('clockwise') ax.set_theta_zero_location('N') ax.set_xticks(np.deg2rad(np.arange(0, 24, 3)*15)) ax.set_xticklabels([str(i) for i in range(0,24,3)] + ['24']) ax.set_yticks([10, 30, 50]) ax.set_yticklabels(['-80', '-60', '-40']) plt.colorbar(sc, label='Energy') plt.title('南极离子能量分布 (MLAT vs MLT)') plt.show()
注意事项
- 地磁转换必须指定准确的观测时间,MLT是时间依赖参数,不同时间海岸线在MLAT-MLT图上的位置会旋转,与参考图效果一致。
- MATLAB若无法获取SPT,可使用
igrf12syn函数手动计算地磁坐标。
内容的提问来源于stack exchange,提问作者steve
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