Python如何简化代码实现列表内容无方括号打印？

Hey there! I’ve got two super straightforward ways to fix this without complicating your code at all. Let’s break them down:

Method 1: Use str.join() with map() #

Since your list contains integers, we first convert each element to a string, then join them all with ', ' as the separator. This avoids the default list string representation (which includes square brackets).

Here’s your modified code:

import random
n = [random.randint(10,999) for i in range(int(input()))]
print(', '.join(map(str, n)))

• map(str, n) converts every integer in the list n to a string.
• ', '.join(...) glues all those strings together with ', ' between each one.

Method 2: Unpack the List with * (Even Simpler!) #

Python lets you unpack list elements directly as arguments to print() using the * operator. Then you just specify the separator with the sep parameter. This is probably the shortest and cleanest solution.

Modified code:

import random
n = [random.randint(10,999) for i in range(int(input()))]
print(*n, sep=', ')

• *n takes every element in the list and passes them as individual arguments to print().
• sep=', ' tells print() to put ', ' between each argument instead of the default space.

Why Your Original Code Didn’t Work #

When you do print(n, end=', '), you’re printing the entire list object, which Python converts to its default string format ([element1, element2, ...]). The two methods above bypass this by printing the elements directly instead of the list itself.

内容的提问来源于stack exchange，提问作者TurtleSam