不使用类外属性实现归并排序的排序键动态切换问题
解决Person类归并排序时的TypeError及封装需求
你遇到的TypeError: 'Person' object is not subscriptable是因为你在lambda里用x[0]这种下标方式访问Person对象,但Person类没有实现__getitem__方法,无法像列表一样通过下标取值。同时你要求不能在Person类外部直接访问其私有属性(_name、_age等),可以通过给Person类提供合法的访问接口来实现需求。
可行方案:通过只读属性暴露排序字段
使用Python的@property装饰器,将私有属性封装成只读的公开属性,这样外部可以通过属性名访问(而非直接访问私有变量),既满足封装要求,又能为排序lambda提供合法的取值方式。
另外,原代码中Person类的__len__方法引用了不存在的self.data,需要修复或移除该方法,否则创建Person对象时会报错。
修改后的完整代码
import numpy as np from merge_sort import mergesort NAMES = ["Alice", "Bob", "Charlie", "David", "Eve", "Frank", "Grace", "Hank", "Ivy", "Jack"] class Person(): def __init__(self, name, age, height, weight): self._name = name self._age = age self._height = height self._weight = weight # 修复__len__方法,返回属性数量 def __len__(self): return 4 def __repr__(self): return f"{self._name}, {self._age} years, {self._height} cm, {self._weight} kg\n" def __eq__(self, other): return (self._age, self._height, self._weight) == (other._age, other._height, other._weight) def __lt__(self, other): return (self._age, self._height, self._weight) < (other._age, other._height, other._weight) def __le__(self, other): return (self._age, self._height, self._weight) <= (other._age, other._height, other._weight) def __gt__(self, other): return (self._age, self._height, self._weight) > (other._age, other._height, other._weight) def __ge__(self, other): return (self._age, self._height, self._weight) >= (other._age, other._height, other._weight) def __int__(self): return int(self._age) def __float__(self): return float(self._age) def __str__(self): return f"{self._name}, {self._age} years, {self._height} cm, {self._weight} kg" # 添加只读属性,封装私有变量 @property def name(self): return self._name @property def age(self): return self._age @property def height(self): return self._height @property def weight(self): return self._weight def create_persons_list(n=10, sort_key='weight'): person_objects = [Person(np.random.choice(NAMES), np.random.randint(18, 101), np.random.randint(150, 201), np.random.randint(45, 101)) for _ in range(n)] # 根据sort_key使用对应的只读属性 if sort_key == 'name': return mergesort(person_objects, key=lambda x: x.name) elif sort_key == 'age': return mergesort(person_objects, key=lambda x: x.age) elif sort_key == 'height': return mergesort(person_objects, key=lambda x: x.height) elif sort_key == 'weight': return mergesort(person_objects, key=lambda x: x.weight) else: raise ValueError("Invalid sort_key. Supported values are 'name', 'age', 'height', and 'weight'.") sorted_persons_by_name = create_persons_list(sort_key='name') sorted_persons_by_age = create_persons_list(sort_key='age') sorted_persons_by_height = create_persons_list(sort_key='height') sorted_persons_by_weight = create_persons_list(sort_key='weight') print("Sorted by name: \n") print(sorted_persons_by_name) print("Sorted by age: \n") print(sorted_persons_by_age) print("Sorted by height: \n") print(sorted_persons_by_height) print("Sorted by weight: \n") print(sorted_persons_by_weight)
其他可选方案
- 添加getter方法:给Person类添加
get_name()、get_age()等方法,lambda写成lambda x: x.get_name(),效果和@property类似,只是调用方式不同。 - 实现__getitem__方法:让Person支持通过键或下标访问属性,比如:
这样原来的def __getitem__(self, key): if key == 0 or key == 'name': return self._name elif key == 1 or key == 'age': return self._age elif key == 2 or key == 'height': return self._height elif key == 3 or key == 'weight': return self._weight else: raise IndexError("Invalid key for Person")lambda x: x[0]就能正常工作,但需要维护下标和属性的对应关系,不如@property直观。
内容的提问来源于stack exchange,提问作者Mosh98
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