Swift中如何移除数组元素中的特定子字符串？

当然可以实现，下面分两种场景给出具体代码：

场景1：仅替换指定子串（得到["House", "House Dog", "House Wife"]） #

遍历数组，对每个元素执行replacingOccurrences(of:with:)方法，只替换" Dad"子串：

let originalArray = ["House Dad", "House Dog", "House Wife"]
let firstStepArray = originalArray.map {
    $0.replacingOccurrences(of: " Dad", with: "")
}
// firstStepArray 结果：["House", "House Dog", "House Wife"]

场景2：批量移除多个目标子串（最终得到["House", "House", "House"]） #

有两种常用实现方式：

方式1：多次调用替换方法 #

对每个元素依次替换所有目标子串：

let finalArray1 = originalArray.map { str in
    str.replacingOccurrences(of: " Dad", with: "")
       .replacingOccurrences(of: " Dog", with: "")
       .replacingOccurrences(of: " Wife", with: "")
}
// finalArray1 结果：["House", "House", "House"]

方式2：正则表达式批量匹配替换 #

用正则表达式一次性匹配所有要移除的后缀子串，更简洁高效：

import Foundation

let suffixRegex = try! NSRegularExpression(pattern: #" (Dad|Dog|Wife)$"#)
let finalArray2 = originalArray.map { str in
    let range = NSRange(str.startIndex..., in: str)
    return suffixRegex.stringByReplacingMatches(in: str, range: range, withTemplate: "")
}
// finalArray2 结果：["House", "House", "House"]

正则表达式中的$确保只匹配字符串末尾的目标子串，避免误替换中间出现的相同内容。

内容的提问来源于stack exchange，提问作者JOHNY