如何让Ansible async_status重试时显示脚本输出而非重试提示？

使用ansible.builtin.expect模块执行交互式脚本，通过ansible.builtin.async_status获取脚本执行状态，但每次重试时仅显示如下重试提示，想实现每次重试时显示脚本输出：

TASK [Wait for the script execution] *******************************************
FAILED - RETRYING: [SERVER1]: Wait for the script execution (100 retries left).
FAILED - RETRYING: [SERVER1]: Wait for the script execution (99 retries left).
FAILED - RETRYING: [SERVER1]: Wait for the script execution (98 retries left).
...

当前使用的Playbook片段：

- name: Execute Shutdown Script
  ansible.builtin.expect:
    command: "./{{ script_file }}"
    responses: "{{ responses }}"
  args:
    chdir: "{{ script_path }}"
  register: script_status
  async: 1000
  poll: 0
  changed_when: not script_status.changed

- name: Wait for the script execution
  ansible.builtin.async_status:
    jid: "{{ script_status.ansible_job_id }}"
  register: script_job_async_result
  until: script_job_async_result.finished
  retries: "{{ script_async_retries | default(100) }}"
  delay: "{{ script_async_delay | default(1) }}"
  when: script_status.ansible_job_id is defined

解决方案 #

方法1：在重试周期内直接打印async_status返回的输出 #

async_status模块会返回异步任务的stdout和stderr字段，将状态检查和输出打印放在同一个任务块中，利用always确保每次重试都执行输出操作：

- name: Wait for script execution and show output
  block:
    - name: Check async job status
      ansible.builtin.async_status:
        jid: "{{ script_status.ansible_job_id }}"
      register: script_job_async_result
      until: script_job_async_result.finished
      retries: "{{ script_async_retries | default(100) }}"
      delay: "{{ script_async_delay | default(1) }}"
      when: script_status.ansible_job_id is defined
  always:
    - name: Print current script output
      debug:
        msg: |
          脚本执行中，当前输出:
          {{ script_job_async_result.stdout | default('无') }}
          当前错误输出:
          {{ script_job_async_result.stderr | default('无') }}
      when: script_status.ansible_job_id is defined

方法2：通过expect日志文件追踪输出 #

让expect模块将脚本执行日志写入远程主机的文件，每次重试时读取该文件内容并打印：

1. 修改执行脚本的任务，添加logfile参数：

- name: Execute Shutdown Script
  ansible.builtin.expect:
    command: "./{{ script_file }}"
    responses: "{{ responses }}"
    logfile: "{{ script_path }}/script_execution.log"
  args:
    chdir: "{{ script_path }}"
  register: script_status
  async: 1000
  poll: 0
  changed_when: not script_status.changed

2. 修改等待任务，配合slurp模块读取并打印日志：

- name: Wait for script execution and show log
  ansible.builtin.async_status:
    jid: "{{ script_status.ansible_job_id }}"
  register: script_job_async_result
  until: script_job_async_result.finished
  retries: "{{ script_async_retries | default(100) }}"
  delay: "{{ script_async_delay | default(1) }}"
  when: script_status.ansible_job_id is defined
  changed_when: false
  notify: Print script execution log

- name: Read script log file
  ansible.builtin.slurp:
    src: "{{ script_path }}/script_execution.log"
  register: script_log_content
  listen: Print script execution log
  when: script_status.ansible_job_id is defined

- name: Display script log
  debug:
    msg: "{{ script_log_content.content | b64decode }}"
  listen: Print script execution log
  when: script_status.ansible_job_id is defined

方法3：调整Ansible输出 verbosity #

如果只是需要临时查看详细输出，可以在运行Playbook时增加-v、-vv或更高级别 verbosity 参数，Ansible会默认展示更多任务执行细节，包括异步任务的输出内容。

内容的提问来源于stack exchange，提问作者Gineesh