请求协助实现Pine Script中的最小公倍数（LCM）计算

Hey there! Let's get that LCM calculation working for you. I spotted a few syntax and logic issues in your code that are holding it back—let's break them down and fix things step by step.

What Was Wrong With the Original Code? #

• Reverse loop logic: Your while loop was only running when z was already a common multiple of x and y—that's the opposite of what we need! We need to keep incrementing z until it meets the divisibility condition.
• Missing variable initialization: The lcm variable wasn't declared before you tried to assign it, which Pine Script doesn't allow.
• Incorrect loop structure: If the initial z (the larger number) wasn't a multiple, your loop would never run, leaving lcm undefined.

Corrected Code (Loop Approach) #

Here's the fixed version of your original loop-based implementation:

//@version=5
indicator(title='LCM Calculator', overlay=false, precision=2, timeframe='')

x = input(15, title="First Number")
y = input(30, title="Second Number")

// Handle edge case: LCM is undefined if either number is 0
if x == 0 or y == 0
    lcm = 0
else
    z = math.max(x, y)
    lcm = z  // Initialize LCM with the larger number first
    // Keep incrementing z until it's divisible by both x and y
    while not (z % x == 0 and z % y == 0)
        z += 1
        lcm = z

plot(lcm, color=color.new(color.black, 0), title="LCM Value")

Even Better: Use GCD for Faster LCM Calculation #

For a more efficient approach (especially with large numbers), you can use the mathematical relationship between LCM and GCD:
LCM(a, b) = (a * b) / GCD(a, b)

Pine Script v5 has a built-in math.gcd() function, so we can avoid looping entirely:

//@version=5
indicator(title='LCM Calculator (GCD Method)', overlay=false, precision=2, timeframe='')

x = input(15, title="First Number")
y = input(30, title="Second Number")

if x == 0 or y == 0
    lcm = 0  // LCM is undefined for 0, default to 0
else
    lcm = (x * y) / math.gcd(x, y)

plot(lcm, color=color.new(color.black, 0), title="LCM Value")

This method is way faster because it skips the iterative loop—perfect for any size of input numbers.

内容的提问来源于stack exchange，提问作者Mavi Beyaz Gökyüzü