如何用jq结合正则替换JSON指定对象的name与rootPath字段

原始JSON数据：

[
  {
    "name": "architecture-design-detailed",
    "rootPath": "/media/ismail/architecture-design-detailed/_Working/_NotesFiltered/_software/architecture-design-detailed",
    "paths": [],
    "group": "",
    "enabled": true
  },
  {
    "name": "architecture-design-detailed-engineering",
    "rootPath": "/media/ismail/architecture-design-detailed/_Working/_NotesFiltered/_software/architecture-design-detailed-engineering",
    "paths": [],
    "group": "",
    "enabled": true
  }
]

需求：当name字段值为architecture-design-detailed时：

• 将name字段修改为new_name_here
• 将rootPath字段中最后一个斜杠后的部分替换为new_name_here

现有jq命令（仅完成name字段修改）：

jq 'map(if .name == "architecture-design-detailed" then .name = "new_name_here" else . end)'

可以通过sub函数匹配rootPath末尾的路径段并替换，结合字段赋值完成两项修改。完整的jq命令如下：

jq 'map(
  if .name == "architecture-design-detailed" then
    .name = "new_name_here" |
    .rootPath |= sub("/[^/]+$"; "/new_name_here")
  else
    .
  end
)'

命令说明： #

• | 用于串联操作，先修改name字段，再处理rootPath
• |= 是更新运算符，专门针对rootPath字段执行后续替换操作
• sub("/[^/]+$"; "/new_name_here")：
  • 正则表达式/[^/]+$匹配最后一个斜杠及其后的所有非斜杠字符（$锚定字符串结尾）
  • 替换为/new_name_here，实现最后一段路径的替换

执行后得到预期输出：

[
  {
    "name": "new_name_here",
    "rootPath": "/media/ismail/architecture-design-detailed/_Working/_NotesFiltered/_software/new_name_here",
    "paths": [],
    "group": "",
    "enabled": true
  },
  {
    "name": "architecture-design-detailed-engineering",
    "rootPath": "/media/ismail/architecture-design-detailed/_Working/_NotesFiltered/_software/architecture-design-detailed-engineering",
    "paths": [],
    "group": "",
    "enabled": true
  }
]

内容的提问来源于stack exchange，提问作者Ahmad Ismail