Clingo初学者求助：合并OR规则及通配符匹配问题

一、合并OR条件规则 #

你可以利用Clingo规则体中的**分号（;）**表示逻辑OR，将两条规则合并为单一规则，同时简化匹配逻辑：

activity("Not", "unknown", "910-248-4781", "2022-12-01", "12:16", "Login", "burner").
activity("Burner", "unknown", "910-248-4781", "2022-12-01", "12:19", "Created My Burner number", "unknown").
activity("Burner", "unknown", "910-248-4781", "2022-12-01", "13:28", "Received Picture", "OG use of Cookies").
activity("Burner", "unknown", "910-248-4781", "2022-12-01", "13:30", "Saved Picture", "OG use of Cookies").
activity("Burner", "unknown", "910-248-4781", "2022-12-01", "13:31", "Sent Message", "burner").

% 合并规则：匹配App或Content字段含"burner"的记录
contains_burner(App, ContactID, PhoneNumber, Date, Time, Action, Content) :- 
    activity(App, ContactID, PhoneNumber, Date, Time, Action, Content),
    (contains_word_burner(Content); contains_word_burner(App)).

% 简化匹配值定义
contains_word_burner("burner").
contains_word_burner("Burner").

#show contains_burner/7.

规则体中的(A; B)表示逻辑OR，只要contains_word_burner(Content)或contains_word_burner(App)任一条件满足，规则就会触发。

二、模糊匹配（子串检查）实现 #

Clingo核心ASP语法无内置模糊匹配功能，但可通过两种方式实现：

1. 纯ASP子串检查 #

通过拆分字符串为字符序列，利用append谓词检查目标子串是否存在：

activity("Not", "unknown", "910-248-4781", "2022-12-01", "12:16", "Login", "burner").
activity("Burner", "unknown", "910-248-4781", "2022-12-01", "12:19", "Created My Burner number", "unknown").
activity("Burner", "unknown", "910-248-4781", "2022-12-01", "13:28", "Received Picture", "OG use of Cookies").
activity("Burner", "unknown", "910-248-4781", "2022-12-01", "13:30", "Saved Picture", "OG use of Cookies").
activity("Burner", "unknown", "910-248-4781", "2022-12-01", "13:31", "Sent Message", "burner").

% 辅助谓词：拆分字符串为字符列表
split_str("", []).
split_str(S, [C|Cs]) :- 
    S = C ++ Rest,
    split_str(Rest, Cs).

% 检查字符串是否包含"burner"子串（大小写兼容）
contains_substr_burner(S) :-
    split_str(S, Chars),
    append(_, ['b','u','r','n','e','r'|_], Chars).
contains_substr_burner(S) :-
    split_str(S, Chars),
    append(_, ['B','u','r','n','e','r'|_], Chars).

% 模糊匹配规则
contains_burner(App, ContactID, PhoneNumber, Date, Time, Action, Content) :- 
    activity(App, ContactID, PhoneNumber, Date, Time, Action, Content),
    (contains_substr_burner(Content); contains_substr_burner(App)).

#show contains_burner/7.

该方法通过字符序列检查实现子串匹配，适合简单场景，复杂模式需额外处理。

2. 利用Clingo Lua扩展（高效方案） #

调用Lua字符串函数直接做子串检查，效率更高：

activity("Not", "unknown", "910-248-4781", "2022-12-01", "12:16", "Login", "burner").
activity("Burner", "unknown", "910-248-4781", "2022-12-01", "12:19", "Created My Burner number", "unknown").
activity("Burner", "unknown", "910-248-4781", "2022-12-01", "13:28", "Received Picture", "OG use of Cookies").
activity("Burner", "unknown", "910-248-4781", "2022-12-01", "13:30", "Saved Picture", "OG use of Cookies").
activity("Burner", "unknown", "910-248-4781", "2022-12-01", "13:31", "Sent Message", "burner").

% 加载Lua扩展脚本
#script(lua)
function contains_burner(s)
    -- 检查是否包含"burner"或"Burner"子串
    return string.find(s, "burner", 1, true) ~= nil or string.find(s, "Burner", 1, true) ~= nil
end
#end.

% 调用Lua函数的匹配规则
contains_burner(App, ContactID, PhoneNumber, Date, Time, Action, Content) :- 
    activity(App, ContactID, PhoneNumber, Date, Time, Action, Content),
    lua_contains_burner(Content);
    activity(App, ContactID, PhoneNumber, Date, Time, Action, Content),
    lua_contains_burner(App).

% 声明外部Lua谓词
#external lua_contains_burner(S) :- lua("contains_burner(S)").

#show contains_burner/7.

该方案依赖Clingo的Lua扩展支持，适合复杂字符串匹配需求。

内容的提问来源于stack exchange，提问作者James Simmons