当变量数据类型指定为short时，单位数数值（含数值1）是否占用16位内存？

Hey there! Let's clear up these two related questions about short variables once and for all.

First off, let's get the core point straight: the memory size of a variable is determined by its declared data type, not the actual value it holds.

For your first question: If a short variable only holds a single-digit number, does it still take up 16 bits? #

Absolutely yes. When you declare a variable as short, the compiler allocates the fixed amount of memory specified for that type (in most systems, that's 16 bits / 2 bytes) right at compile time. It doesn't matter if you store 5, 9, or any other value within the short range—it's still going to use the full 16 bits. The small value doesn't get "packed" into fewer bits to save space.

For your second question: If a short variable holds the value 1, does it take up 16 bits? #

Same answer here! Storing 1 in a short variable doesn't change its memory footprint. The 1 will be represented as a 16-bit binary number (something like 00000000 00000001), and the entire 16 bits are reserved for that variable.

To put this into code context (taking C/C++ as an example):

// Both variables below occupy 16 bits of memory
short single_digit = 7;
short value_one = 1;

A quick note on edge cases: The only time a short-related variable might use fewer bits is if you explicitly use a bit field (like in a struct), where you can specify the number of bits to use, e.g.:

struct SmallValue {
    short num : 4; // This uses only 4 bits, not 16
};

But this is a special, intentional case—regular short variables will always use their full fixed size.

内容的提问来源于stack exchange，提问作者y z