如何根据name字段复制数组内嵌套对象的指定字段

需求说明 #

需要将JSON数据中gpu.id为"zebra"的sum值，复制到gpu.id为"fish"的sum字段中，且不依赖数组元素的顺序。

原始输入JSON #

{
  "zoo": [
    { "room": { "name": "x" }, "gpu": { "id": "fish",  "sum": 0 } },
    { "room": { "name": "y" }, "gpu": { "id": "zebra", "sum": 797 } }
  ]
}

实现代码（JavaScript） #

const data = {
  "zoo": [
    { "room": { "name": "x" }, "gpu": { "id": "fish",  "sum": 0 } },
    { "room": { "name": "y" }, "gpu": { "id": "zebra", "sum": 797 } }
  ]
};

// 查找zebra的sum值
const zebraSum = data.zoo.find(item => item.gpu.id === "zebra")?.gpu.sum;

// 找到fish并更新sum值
if (zebraSum !== undefined) {
  const fishEntry = data.zoo.find(item => item.gpu.id === "fish");
  if (fishEntry) {
    fishEntry.gpu.sum = zebraSum;
  }
}

// 输出处理后的JSON
console.log(JSON.stringify(data, null, 2));

处理后的输出JSON #

{
  "zoo": [
    { "room": { "name": "x" }, "gpu": { "id": "fish",  "sum": 797 } },
    { "room": { "name": "y" }, "gpu": { "id": "zebra", "sum": 797 } }
  ]
}

说明 #

• 使用Array.find()方法通过gpu.id匹配目标元素，完全不依赖数组的顺序
• 加入了可选链（?.）和存在性判断，避免因找不到目标元素导致报错

内容的提问来源于stack exchange，提问作者Udi