Instagram关注机器人无法点击关注按钮及滚动列表问题求助

解决方案 #

1. 更新元素定位器（适配Instagram最新页面结构）

原代码中使用的isgrP类名已被Instagram废弃，当前粉丝列表弹窗的滚动容器类名为_aano，修改等待逻辑：

followers_list = WebDriverWait(self.driver, 10).until(
    EC.visibility_of_element_located((By.XPATH, "//div[@role='dialog']//div[@class='_aano']"))
)

2. 替换为可靠的JavaScript滚动

原Space键滚动方式不稳定，改用JS控制滚动容器的滚动条：

# 替换原滚动循环代码
last_height = self.driver.execute_script("return arguments[0].scrollHeight", followers_list)
while True:
    # 滚动到底部
    self.driver.execute_script("arguments[0].scrollTop = arguments[0].scrollHeight", followers_list)
    time.sleep(2)  # 等待加载新内容
    new_height = self.driver.execute_script("return arguments[0].scrollHeight", followers_list)
    # 高度不变说明已加载完所有内容
    if new_height == last_height:
        break
    last_height = new_height

3. 修复关注按钮定位逻辑

直接通过文本定位容易失效，改用按钮的特征类名定位，并跳过已关注的按钮：

def follow(self):
    try:
        # 定位所有未关注的按钮
        buttons = self.driver.find_elements(By.XPATH, "//button[contains(@class, '_acan') and contains(@class, '_acap') and contains(@class, '_acas')]")
        for button in buttons:
            # 只处理显示"Follow"的按钮
            if button.text.strip() == "Follow":
                self.driver.execute_script("arguments[0].scrollIntoView({block: 'center'});", button)
                time.sleep(1)
                button.click()
                time.sleep(3)
    except Exception as e:
        print(e)

4. 升级ChromeDriver初始化方式

executable_path已被Selenium弃用，改用Service类初始化：

def __init__(self, path):
    service = Service(path)
    self.driver = webdriver.Chrome(service=service)

5. 处理登录后的弹窗

登录后会出现"保存登录信息"和"通知权限"弹窗，需添加处理逻辑避免阻塞：

def login(self):
    self.driver.get(url=INSTA_URL)
    time.sleep(3)
    # 输入账号密码
    username = self.driver.find_element(By.NAME, value="username")
    username.send_keys(INSTA_USERNAME)
    password = self.driver.find_element(By.NAME, value="password")
    password.send_keys(INSTA_PASSWORD)
    password.send_keys(Keys.ENTER)
    time.sleep(5)
    # 关闭"保存登录信息"弹窗
    try:
        not_now = self.driver.find_element(By.XPATH, "//div[text()='Not Now']")
        not_now.click()
        time.sleep(3)
    except:
        pass
    # 关闭"通知权限"弹窗
    try:
        not_now_notif = self.driver.find_element(By.XPATH, "//button[text()='Not Now']")
        not_now_notif.click()
        time.sleep(3)
    except:
        pass

内容的提问来源于stack exchange，提问作者Ziya Safar