自动判分工具误将输入识别为输出导致代码报错求助

你的自动判分工具误把输入提示当成输出，大概率是因为平台会捕获input()函数的提示文本作为输出内容，或者代码的输出格式不符合工具预期。以下是针对性修改方案：

方案1：分离输入提示与输入操作 #

把input()里的提示文本单独用print()输出，避免平台将提示误判为输出：

print("What is the first of the two numbers you would like to check?: ")
first_number = int(input())
print("what is the second of the two numbers you would like to check?: ")
last_number = int(input())

def number_is_a_prime_number(number):
    if number < 2:
        return False
    for i in range(2, round(number/2) + 1):
        if number % i == 0:
            return False
    return True

def primes_to_be_listed(first, last):
    prime_list = []
    for number in range(first, last + 1):
        if number_is_a_prime_number(number):
            prime_list.append(number)
    print(f"The list of prime numbers between {first} and {last}:")
    for prime in prime_list:
        print(prime)

primes_to_be_listed(first_number,last_number)

方案2：移除所有输入提示（适用于平台不允许输出提示的情况） #

如果判分工具只接受纯输出结果，直接去掉所有提示文本，仅保留输入逻辑：

first_number = int(input())
last_number = int(input())

def number_is_a_prime_number(number):
    if number < 2:
        return False
    for i in range(2, round(number/2) + 1):
        if number % i == 0:
            return False
    return True

def primes_to_be_listed(first, last):
    prime_list = []
    for number in range(first, last + 1):
        if number_is_a_prime_number(number):
            prime_list.append(number)
    print(f"The list of prime numbers between {first} and {last}:")
    for prime in prime_list:
        print(prime)

primes_to_be_listed(first_number,last_number)

额外修正：去掉输出的多余换行 #

原代码中print(f"...:\n")多了一个换行，可能导致输出格式不符，修改为直接输出标题即可，确保和工具预期的输出格式完全匹配。

内容的提问来源于stack exchange，提问作者D1ZZY