Python实现按间隔批量更新范围内元素的小时区间问题

Corrected Code #

from datetime import datetime

utc_time = datetime.utcnow()
utc_hour = utc_time.hour

minute = []
hour = []
day = []
month = []
week = []

_hour = utc_hour
count = 0
elements_per_group = 3
total_elements = 12
layer = 'get'  # Define the missing variable

while count < total_elements:
    if layer == 'get':
        minute.append('0-59')
        
        # Shift the hour interval every time we start a new group
        if count != 0 and count % elements_per_group == 0:
            _hour += 4
        
        end_hour = _hour + 4
        hour_interval = f"{_hour}-{end_hour}"
        hour.append(hour_interval)
        
        print(count, elements_per_group, hour)
    
    count += 1

What Was Wrong & How We Fixed It #

1. Missing Variables: The original code used layer and x without defining them—this would throw a NameError. We added layer = 'get' and removed the undefined x from the print statement.
2. No Interval Progression: The _hour variable was never updated, so every element got the same starting interval. We added logic to increment _hour by 4 each time we start a new group (after every 3 elements).
3. Extra Element: The loop ran count <= 12, which creates 13 elements instead of 12. Changing it to count < 12 fixes this.
4. Redundant Code: The line a = [hour.append(gen_hour)] was unnecessary—hour.append() modifies the list directly, and wrapping it in a list just creates a list with a None value. We removed this line.

Example Result (UTC Hour = 6) #

The hour list will now correctly group intervals:

['6-10', '6-10', '6-10', '10-14', '10-14', '10-14', '14-18', '14-18', '14-18', '18-22', '18-22', '18-22']

内容的提问来源于stack exchange，提问作者devi