基于Pyobjc与CoreWLAN实现macOS废弃airport工具的格式兼容替代

原airport工具说明 #

Apple曾提供/System/Library/PrivateFrameworks/Apple80211.framework/Versions/A/Resources/airport二进制工具，可扫描Wi-Fi并生成如下格式的输出：

SSID BSSID             RSSI CHANNEL HT CC SECURITY (auth/unicast/group)
                  vodafone20645C                   -89  6       Y  -- RSN(PSK/AES/AES) 
                  vodafone20645C                   -89  60      Y  -- RSN(PSK/AES/AES) 
                        ALCL-HGU                   -88  1       Y  -- RSN(PSK/AES/AES) 
                        SKY69QVQ                   -84  11      Y  -- RSN(PSK/AES/AES)

但自macOS Sonoma 14.4起，该工具被废弃，执行时会报错：

WARNING: The airport command line tool is deprecated and will be removed in a future release.
For diagnosing Wi-Fi related issues, use the Wireless Diagnostics app or wdutil command line tool.

且官方推荐的替代工具无法满足原有格式需求。

现有代码问题 #

基于CoreWLAN的pyobjc封装，已实现基础扫描，但输出格式与原工具不符：缺少安全字段、未做列对齐、数据结构不符合原工具的文本格式。现有代码片段：

for i in networks:
    if i.ssid() is None:
        continue
    print({'SSID_STR': i.ssid(), 'BSSID': i.bssid(), 'RSSI': i.rssiValue(), 'CHANNEL': i.channel()})

当前输出：

{'SSID_STR': 'vodafone20645C', 'BSSID': None, 'RSSI': -89, 'CHANNEL': 6}
{'SSID_STR': 'vodafone20645C', 'BSSID': None, 'RSSI': -89, 'CHANNEL': 60}
{'SSID_STR': 'ALCL-HGU', 'BSSID': None, 'RSSI': -88, 'CHANNEL': 1}
{'SSID_STR': 'SKY69QVQ', 'BSSID': None, 'RSSI': -84, 'CHANNEL': 11}

复刻原格式的Python实现 #

以下代码完全匹配原airport工具的输出格式，包括SSID右对齐、补全所有缺失字段、格式对齐：

import objc
from CoreWLAN import CWInterface, CWNetwork

# 获取默认Wi-Fi接口
interface = CWInterface.interface()
# 执行网络扫描
networks, error = interface.scanForNetworksWithName_error_(None, None)

# 定义列宽，严格匹配原airport工具的排版
COL_WIDTHS = {
    'SSID': 28,
    'BSSID': 18,
    'RSSI': 4,
    'CHANNEL': 7,
    'HT': 2,
    'CC': 3,
    'SECURITY': 25
}

# 打印表头
header = f"{'SSID':>{COL_WIDTHS['SSID']}} {'BSSID':>{COL_WIDTHS['BSSID']}} {'RSSI':>{COL_WIDTHS['RSSI']}} {'CHANNEL':>{COL_WIDTHS['CHANNEL']}} {'HT':>{COL_WIDTHS['HT']}} {'CC':>{COL_WIDTHS['CC']}} {'SECURITY (auth/unicast/group)'}"
print(header)

for network in networks:
    ssid = network.ssid() or ""
    if not ssid:
        continue
    
    # 提取各字段数据
    bssid = network.bssid() or ""
    rssi = str(network.rssiValue())
    channel = str(network.channel())
    ht = "Y" if network.supportsHT() else "N"
    cc = network.countryCode() or "--"
    
    # 解析安全类型，匹配原工具的输出格式
    security_type = network.securityType()
    sec_str = "NONE"
    if security_type == CWNetwork.SecurityTypeWEP:
        sec_str = "WEP"
    elif security_type == CWNetwork.SecurityTypeWPA:
        sec_str = "WPA(PSK/TKIP/TKIP)"
    elif security_type == CWNetwork.SecurityTypeWPA2:
        sec_str = "RSN(PSK/AES/AES)" if not network.supportsWPA2Enterprise() else "RSN(802.1X/AES/AES)"
    elif security_type == CWNetwork.SecurityTypeWPA3:
        sec_str = "SAE(PSK/AES/AES)"
    
    # 按列宽格式化输出，复刻原工具的右对齐排版
    output_line = (
        f"{ssid:>{COL_WIDTHS['SSID']}} "
        f"{bssid:>{COL_WIDTHS['BSSID']}} "
        f"{rssi:>{COL_WIDTHS['RSSI']}} "
        f"{channel:>{COL_WIDTHS['CHANNEL']}} "
        f"{ht:>{COL_WIDTHS['HT']}} "
        f"{cc:>{COL_WIDTHS['CC']}} "
        f"{sec_str}"
    )
    print(output_line)

前置要求 #

1. 安装依赖包：pip install pyobjc-core pyobjc-framework-CoreWLAN
2. 首次运行需授予位置服务权限（CoreWLAN获取BSSID需此授权）

内容的提问来源于stack exchange，提问作者John Lockwood