如何在trigger_device中订阅TriggeredEvent？类型不兼容问题求解

错误原因 #

CC.TriggeredEvent.Subscribe要求的回调函数类型为?agent->void，但你定义的OnTriggeredEvent带有<suspends>修饰符，属于挂起函数，二者类型不兼容，导致报错。此外原代码中OnTriggeredEvent定义在类外部，无法访问类的成员变量，会引发额外问题。

解决方案 #

做两处关键修改：

• 移除OnTriggeredEvent的<suspends>修饰符（你的回调逻辑里没有Sleep、Await这类需要挂起的操作）
• 将OnTriggeredEvent移入MapLoader类内部，确保能访问类成员变量

修正后的完整代码 #

using { /Fortnite.com/Devices }
using { /Verse.org/Simulation }
using { /UnrealEngine.com/Temporary/Diagnostics }

# A Verse-authored creative device that can be placed in a level
MapLoader := class(creative_device):

    @editable
    CC:trigger_device = trigger_device{}

    @editable
    MapText:billboard_device = billboard_device{}

    @editable
    DifficultyText:billboard_device = billboard_device{}

    var initseconds : int = 0

    @editable
    StartTimer:billboard_device = billboard_device{}

    @editable
    RNG:rng_device = rng_device{}

    @editable
    InitTimerInit:trigger_device = trigger_device{}

    StringToMessage<localizes>(value:string)<computes> : message = "{value}"

    OnBegin<override>()<suspends>:void=
        Print("Script started")

        MapText.SetText(StringToMessage("Waiting for player(s).."))
        DifficultyText.SetText(StringToMessage(" "))
        StartTimer.SetText(StringToMessage("{initseconds}s"))
        Print("Defaults set")
        

        InitTimerInit.TriggeredEvent.Await()
        Print("I saw a TriggeredEvent")
        set initseconds = 10
        Print("initseconds set")
        loop:
            if (initseconds > 0):
                set initseconds = initseconds - 1
                Sleep(1.0)
                StartTimer.SetText(StringToMessage("{initseconds}s"))
                Print("{initseconds}")
            else:
                StartTimer.SetText(StringToMessage("{initseconds}s"))
                Print("Done")
                RNG.Activate()
                CC.TriggeredEvent.Subscribe(OnTriggeredEvent)
                break

    OnTriggeredEvent<private>(Agent:agent):void=
        MapText.SetText(StringToMessage("Castaway Castles"))
        DifficultyText.SetText(StringToMessage("EASY"))

内容的提问来源于stack exchange，提问作者Brave.